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3 years ago

What is the value of X plz help

Mathematics

1 answer:

Tema [17]3 years ago

5 0

Answer:

x = 16

Step-by-step explanation:

(5x + 12)° + (6x - 8)° = 180°

(5x + 12 + 6x - 8)° = 180°

(11x + 4)° = 180°

11x + 4 = 180

11x = 180- 4

11x = 176

x = 176/11

x = 16

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If secθ = 13\5 and 270° < θ < 360°, then tanθ = _____. -12\5 -5\12 5\12 12\5

r-ruslan [8.4K]

Answer:

tanΘ = - $\frac{12}{5}$

Step-by-step explanation:

Using the trigonometric identity

tan²Θ + 1 = sec²Θ, thus

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tanΘ = ± $\sqrt{\frac{144}{25} }$

Since 270 < Θ < 360 , that is the fourth quadrant where tan Θ < 0, thus

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4 0

3 years ago

Name the edges of an hexagonal pyramid

aleksandrvk [35]

Given:

Hexagonal pyramid

To find:

The edges of an hexagonal pyramid.

Solution:

Edges means lines which connecting to vertices.

Edges in the base of the pyramid:

AB, BC, CD, DE, EF, FA

Edges in the triangular shape of the pyramid:

AG, BG, CG, DG, EG, FG

Therefore edges of an hexagonal pyramid are:

AB, BC, CD, DE, EF, FA, AG, BG, CG, DG, EG, FG

4 0

3 years ago

Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)

melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

$f_x = \dfrac{x^2}{a^7-x^7}$

$= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}$

$= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}$

since $\Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)$

Then, it implies that:

$\implies \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}$

$\mathbf{= \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}$

7 0

2 years ago

At a certain time of day, a pole, 5 meters tall, casts a 3-meter tall shadow. The shadow of a building next to the pole is 18 me

algol [13]

Answer:

Length of the building = 30 meters

Step-by-step explanation:

Given:

Length of pole = 5 meters

Length of shadow of pole = 3 meters

Length of shadow of the building = 18 meters

To find length of the building.

Solution:

On drawing the figure of the given situation, we get two similar triangles.

Applying proportionality theorem of similar triangles.

$\frac{AB}{BC}=\frac{DE}{EC}$

Plugging in the given lengths.

$\frac{AB}{18}=\frac{5}{3}$

Multiplying both sides by 18.

$\frac{AB}{18}\times 18=\frac{5}{3}\times 18$

$AB=\frac{90}{3}$

$AB=30$

Thus, length of the building = 30 meters

3 0

3 years ago

For every 72 students there are 16 females. If there are 4 females, about how many students are there?

Whitepunk [10]

Answer:

14 im pertty sure

Step-by-step explanation:

8 0

3 years ago