Answer:
The answer would be A, D, and C.
Step-by-step explanation:
y=1, so
1 > 2(1) -2
1> 2-2
1>0 TRUE
NEXT.
y=3
3> 2(-1) -2
3>-2-2
3> -4 TRUE
NEXT
y=-2
4>2(2) -2
4 > 4-2
4>2 TRUE!
I hope this helps!
Answer:
5/2x, 5/2 y
Step-by-step explanation:
An enlargement means the scale factor must be greater than one
The only choice with a scale factor greater than one is 5/2x, 5/2 y
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
The question is incomplete, so I will describe the sine regression model.
The function
y = 0.884 sin(0.245x - 1.093) + 0.400
correspond to the general equation:
y = a sin(bx - c) + d
where:
a = 0.884
b = 0.245
c = 1.093
d = 0.400
The amplitude of the function is computed as follows:
amplitude = |a| = 0.884
The period of the function is computed as follows:
period = 2π/|b| = 25.6456
The phase shift of the function is computed as follows:
phase shift = c/b = 4.4612 to the right (because there is a minus sign before c in the equation)
The vertical shift of the function is computed as follows:
vertical shift = d = 0.400