Answer:
Step-by-step explanation:
At the start of the day there are g pounds of gravel in the quarry.
Then it says that there were 300 pounds added to the mound, so at this point the pounds of gravel in the mound are now g+300.
Then two orders of 700 pounds are sold and removed from the mound. That means they removed 700 pounds from the mound 2 times. Therefore at this point the pounds of gravel in the mound are now g+300-700-700.
Then it says that at this point, the amount of pounds in the mound are 1500. Hence we get
To solve for g we just add 700 two times to both sides of the equation, and subtract 300 from both sides of the equation, getting:
And so 
Answer:
20 I think
Step-by-step explanation:
I mean I would say it is 20
Answer:
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
The number of times I would expect to roll a number that is not a 5 is 300 times.
<h3>What is the number of times a 5 won't be rolled?</h3>
A standard die has 6 faces. There are 5 numbers that are not 5 on a standard die. They are 1, 2, 3, 4, 6.
The number of times a 5 won't be rolled = (5/6) x 360
5 x 60 = 300 times
To learn more about a standard die, please check: brainly.com/question/20376457
#SPJ1
Answer:
QR / SQ = SQ / TQ
Step-by-step explanation:
∠QST = 90 - ∠Q
∠R = 90 - ∠Q
∠QST = ∠R
ΔQST ~ ΔQRS
SQ / TQ = QR / SQ
