Suppose that a box contains 6 cameras and that 3 of them are defective. A sample of 2 cameras is selected at random. Define the
random variable X as the number of defective cameras in the sample.
2 answers:
Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
Answer:
a.
The probability of X
k P(X=k)
0 0.25
1 0.5
2 0.25
b. The expected variable value of X; E(X) = 1
Step-by-step explanation:
Given that:
number of cameras = 6
numbers of defective = 3
the probability of defective camera p = 3/6 = 0.5
sample size n = 2
Then X = {0,1,2}
Suppose X is the given variable that represents the number of defective cameras in the sample.
∴
X
Bin (n =2, p = 0.5)
The probability mass function of binomial distribution can be computed as :

For ;
x = 0
The probability P(X=0) 



For :
x = 1
The probability P(X=1) 



For :
x = 2
The probability P(X=2) 



The probability of X
k P(X=k)
0 0.25
1 0.5
2 0.25
The expected variable value of X can be computed as:
E(X) = np
E(X) = 2 × 0.5
E(X) = 1
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Step-by-step explanation:
You are looking for a unit rate of cents per mile.
Change the dollar amount to cents, and divide by the number of miles.
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Answer:
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Step-by-step explanation:
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Answer: 3
Step-by-step explanation
9 divided by 2 =4.5
3 divided by 2 = 1.5
so then we do 4.5 divided by 1.5=3 so the answer is 3