(3x+4)+(5x2-1)+(2x+6)
remove unnecessary parenthesis
3x+4+(5x2-1)+(2x+6)
3x+4+(10-1)+2x+6
subtract the numbers
3x+4+9+2x+6
collect the like terms
5x+4+4+9+6
5x+19
1/x^-7
It would look more like 1
------
-7 (as an exponent)
x
A = 10 or a = -10
When you square a number, you're essentially multiplying it by itself.
Recall that multiplying two negative numbers will result in a positive numbers. Knowing this, we know that -10 times -10 equals 100.
Given:
Current revenue = $6000
<span>R(f)= -100f^2 + 400f + 6000
where f is a whole number of $5 fee increases
We are told to find f, when R(f) </span><span>< 6000
Since </span>R(f)= -100f^2+400f+6000
R(f) < 6000 ⇒ -100f^2+400f+6000 < 6000
Subtract 6000 from both sides
-100f^2 + 400f + 6000 - 6000 < 6000 - 6000
-100f^2 + 400f < 0
⇒ 400f - 100f^2 < 0
Divide the equation by 100
400f/100 - 100f^2/100 < 0/100
4f - f^2 < 0
Add f^2 to both sides of the equation
4f - f^2 + f^2 < 0 + f^2
4f < f^2
Divide both sides by f
4f/f < (f^2)/f
4 < f
⇒ f > 4
⇒ f ≥ 5
Therefore, <span> for 5 or more numbers of $5 fee increases, the revenue from fees will actually be less than its current value.</span>
