Given:
Image of the ellipse
To find:
The equation of the image
Solution:
The given image is a ellipse.
Center of the ellipse = (0, 0)
x-axis points are (-3, 0) and (3, 0).
y-axis points are (2, 0) and (-2, 0).
Standard form of equation of ellipse:

where (h, k) is the center = (0,0)
a is the point on x-axis where y = 0. Hence a = 3.
b is the point on y-axis where x = 0. Hence b = 2.
Substitute this in the standard form of ellipse.


To make the denominator same multiply 1st term by
and 2nd term by
.



Multiply by 36 on both sides


The equation of the image is
.
The answer i came up with is : (4b-7x) (a+2)
Answer:
Given the radical form: 
Use the exponent rules:
![\sqrt[n]{a^m} = (a^m)^{\frac{1}{n}} = a^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20%28a%5Em%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%20%3D%20a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
we can write
as:

then;
= 
Therefore,
in exponential form is 
Answer:
q=9
Step-by-step explanation:
44-1+7q=106
43+7q=106
7q=63
q=9