10 ft

Mathematics

1 answer:

Lelu [443]2 years ago

3 0

Answer:

P = 40.56 ft

Step-by-step explanation:

The figure is composed of a rectangle and half circle

The perimeter of the figure = the length of the borders round the figure

= W + 2L + ½(perimeter of full circle)

W = 8 ft

L = 10 ft

½(perimeter of circle) = ½(πd) = ½(3.14*8)

= 12.56 ft

Plug in the values

Perimeter of the figure = 8 + 2(10) + 12.56

= 8 + 20 + 12.56

= 40.56 ft

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Ad is tangent to circle o at d. find ab. round to the nearest tenth if necessary

Naddik [55]

Check the picture below.

$\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}
\\\\\\
AB=-3\pm\sqrt{130}\implies AB=
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\boxed{-3+\sqrt{130}}\\\\
-3-\sqrt{130}
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since the distance AB cannot be a negative value, thus is not -3-√(130).