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Keith_Richards [23]
3 years ago
12

What are the first 3 common multiples of 12 and 28

Mathematics
2 answers:
AlexFokin [52]3 years ago
4 0
84, 168, 252.
Hope this helps.
german3 years ago
4 0
I think it would be 84 and 168
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An airliner carries 150 passengers and has doors with a height of 78 in. Heights of men are normally distributed with a mean of
iogann1982 [59]

Answer:

Step-by-step explanation:

x, height of men is N(69, 2.8)

Sample size n =150

Hence sample std dev = \frac{2.8}{\sqrt{150} } =0.229

Hence Z score = \frac{x-69}{0.229}

A) Prob that a random man from 150  can fit without bending

= P(X<78) = P(Z<3.214)=1.0000

B) n =75

Sample std dev = \frac{2.8}{\sqrt{75} } =0.3233

P(X bar <72) = P(Z<9.28) = 1.00

C) Prob of B is more relevent because average male passengers  would be more relevant than a single person

(D) The probability from part (b) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height.

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3 years ago
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pashok25 [27]

Answer:

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Step-by-step explanation:

4 0
2 years ago
Select the equation that represents the problem. Let × represent the unknown number.
kondor19780726 [428]

Answer:

the is option d cause big number is divided by small ones.

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
PLEASE HELP
shusha [124]
15 meals x $0.80 = $12.
$18 - $12 = $6.

If one movie ticket is $3 then she must have purchased 2 with $6.

Part A - 15x0.8=18-x=x

Part B-
15 x 0.8 = 12
18- 12=6

Part C- 2

6 0
3 years ago
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Find a homogeneous linear differential equation with constant coefficients whose general solution is given by
frez [133]

Answer:

y" + 2y' + 2y = 0

Step-by-step explanation:

Given

y=c_1e^{-x}cosx+c_2e^{-x}sinx

Required

Determine a homogeneous linear differential equation

Rewrite the expression as:

y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)

Where

\alpha = -1 and \beta = 1

For a homogeneous linear differential equation, the repeated value m is given as:

m = \alpha \± \beta i

Substitute values for \alpha and \beta

m = -1 \± 1*i

m = -1 \± i

Add 1 to both sides

m +1= 1 -1 \± i

m +1= \± i

Square both sides

(m +1)^2= (\± i)^2

m^2 + m + m + 1 = i^2

m^2 + 2m + 1 = i^2

In complex numbers:

i^2 = -1

So, the expression becomes:

m^2 + 2m + 1 = -1

Add 1 to both sides

m^2 + 2m + 1 +1= -1+1

m^2 + 2m + 2= 0

This corresponds to the homogeneous linear differential equation

y" + 2y' + 2y = 0

6 0
3 years ago
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