Answer:
<u>R</u><u>a</u><u>t</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>1</u><u>.</u><u>1</u><u>3</u><u>3</u><u>3</u><u> </u><u>w</u><u>o</u><u>r</u><u>d</u><u>s</u><u> </u><u>p</u><u>e</u><u>r</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u>
Step-by-step explanation:
We understand rating as frequency or speed of doing something per time (seconds mainly)
![{ \green{ \tt{rate = \frac{item \: quantity}{time} }}} \\](https://tex.z-dn.net/?f=%7B%20%5Cgreen%7B%20%5Ctt%7Brate%20%3D%20%5Cfrac%7Bitem%20%5C%3A%20quantity%7D%7Btime%7D%20%20%7D%7D%7D%20%5C%5C%20)
Let's find rate in terms of seconds (words per second)
![{ \rm{rate = \frac{34 \: words}{ (\frac{1}{2} \times 60) \: seconds} }} \\ \\ { \rm{rate = \frac{34}{30} }} \\ \\ { \rm{rate = 1.133 \: \: words \: per \: second}}](https://tex.z-dn.net/?f=%7B%20%5Crm%7Brate%20%3D%20%20%5Cfrac%7B34%20%5C%3A%20words%7D%7B%20%28%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%2060%29%20%20%5C%3A%20seconds%7D%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7Brate%20%3D%20%20%5Cfrac%7B34%7D%7B30%7D%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7Brate%20%3D%201.133%20%5C%3A%20%20%5C%3A%20words%20%5C%3A%20per%20%5C%3A%20second%7D%7D)
1. x = 16
2. x = 46
Good luck
Three main methods come to mind: Substitution method, Elimination method, Matrix row-reduction.The first two methods are taught in early grades in most high schools. Matrix row-reduction is taught in senior years in high school, or more likely, in the early years of a university math or science program.
Answer:
-S = 15
Step-by-step explanation:
You are asked to find the opposite of the given value.
<h3>Opposite</h3>
The opposite of an integer value is obtained by changing its sign.
S = -15
-S = -(-15) = 15
__
<em>Additional comment</em>
Equivalently, you are multiplying by -1. The product of an even number of minus signs is a plus sign. We usually don't write the plus sign for a numerical value.