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forsale [732]
3 years ago
15

Please help on 6-8!! 20 points

Mathematics
2 answers:
Marta_Voda [28]3 years ago
8 0
6. 5 shirts  20 minutes Multiply both by 3 to get to 60 minutes 15 shirts  60 minutes 15 shirts per hour 
7. 250 miles + 50 miles = 300 miles 300 miles / 5 hours = 60 miles per hour
8. 360 pages / 12 hours = 30 pages per hour400 pages / 30 pages per hour = 13 1/3 hours = 13 hours and 20 minutes
alex41 [277]3 years ago
6 0
6) 20 minutes is 1/3 of an hour.  To find out how many T-shirts per hour, we multiply how many can be produced in 20 minutes by 3.

5 T-shirts X 3 =
15 T-shirts per hour.

7) From Jefferson to Paxten overall, it's 300 miles.  Since we're determining miles per hour, we divide 300 by 5 to find out how fast he was travelling.

300 / 5 = 60 MPH

8) This problem explains a fraction, we just have to find the corresponding fraction with a missing denominator.

360 / 12
400 / ?

360 / 400 = 9 / 10

Multiplying the reciprocal by 12 will give us the answer.

(10 / 9) X 12 = 13 Hours and 20 Minutes.


Hope this helps!
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In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from
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Answer:

a) The point estimate of the proportion of people aged 65–69 who are working is p=0.3 or 30%.

b) We can express this null and alternative hypothesis as:

H_0: \pi=0.27\\H_1:\pi\neq0.27

c) We conclude that there is not enough evidence that the proportion of people aged 65–69 who are working has increased from 2005.

Step-by-step explanation:

a) Develop a point estimate of the proportion of people aged 65–69 who are working

If we take into account the sample taken, the point estimate is

p=\frac{180}{600} =0.3

b) Set up a hypothesis test so that the rejection of h0 will allow you to conclude that theproportion of people aged 65–69 working has increased from 2005

To conclude some claim, we have to reject the null hypothesis. In this case, to claim that the proportion has changed and the mean is no longer 27%, we have to reject the null hypotesis that π=0.27.

We can express this null and alternative hypothesis as:

H_0: \pi=0.27\\H_1:\pi\neq0.27

c) Conduct your hypothesis test using α=0.05. What is your conclusion?

First we calculate the standard deviation, as we will need it to calculate the test statistic:

\sigma=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.27(1-0.27)}{600} }=0.01812

In this case, we have a test statistic of

z=\frac{p-\pi-0.5/N}{\sigma} =\frac{0.3-0.27-0.5/600}{0.01812}=1.61

If we take into account that it is a two-tailed test, P-value for z=1.61 is P=0.1074.

As the P-value is bigger than the significance level, the effect is not statistically significant, so the hypothesis can not be rejected.

We conclude that there is not enough evidence that the proportion of people aged 65–69 who are working has increased from 2005.

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