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2 years ago

Put these fractions in order of size

Mathematics

1 answer:

KIM [24]2 years ago

5 0

1/6 = 4/24
3/8 = 9/24
11/24
1/3 = 8/24
5/12 = 10/24

1/6, 1/3, 3/8, 5/12, 11/24

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A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose fr

quester [9]

Answer: She could create 60 platters.

Step-by-step explanation:

Given: A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose from.

Number of combinations of selecting <em>r</em> things from <em>n</em> things is given by:-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

So, the number of combinations of selecting 2 different vegetables from 6 = $^6C_2=\dfrac{6!}{2!4!}=\dfrac{6\times5}{2}=15$

Now, By Fundamental counting principle, the number of different platters she could create = (number of ways of selecting 2 different vegetables from 6) x (Number of sizes)

= 15 x 4

= 60

Hence, she could create 60 platters.

6 0

2 years ago

Identify the coefficient and the exponent for each term of 8x ^ 4 - 2x

velikii [3]

Step-by-step explanation:

Given binomial is: $8x^4 - 2x$

$in \: the \: term \: 8 {x}^{4} \\ coefficient = 8 \\ exponent = 4 \\ \\ in \: the \: term \: - 2x \\ coefficient = - 2 \\ exponent = 1$

4 0

2 years ago

The sum of 3 consecutive odd numbers is 51. What is the second number in this sequence?

Feliz [49]

$2n+1+2n+3+2n+5=51\\
6n+9=51\\
6n=42\\
n=7\\\\
2n+3=2\cdot7+3=17$

4 0

3 years ago

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m

borishaifa [10]

Answer:

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

Step-by-step explanation:

Air containing 0.04% carbon dioxide

V, volume of room is 6000 ft3.

Q, rate of air 2000 ft3/min,

initial concentration of 0.4% carbon dioxide,

determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes?

firstly, we find the time taken for air to completely filled the room

Q = V/t

t = V/Q = 6000/2000 = 3min

so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.

there is an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.

therefore,

3mins = 0.04% of CO2

3*60 =180sec = 0.04%

1sec = 0.04/180 = 0.00022%/sec

so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec

What is the concentration at 10 minute

the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.

for 0.04% = 6000ft3

? = 2000ft3

= 2000* 0.04)/6000 =0.0133%

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

4 0

3 years ago

Type the correct answer in each box. if necessary, round your answers to the nearest hundredth

Vesnalui [34]

Answer:

i need the problem

Step-by-step explanation:

plas give problem so i couuld solve

6 0

2 years ago

Read 2 more answers