Answer:
Step-by-step explanation:
The rate if increase of side of square is 7cm/s
dL/dt=7
At what area is the area increasing
dA/dt=?
Areas of square is give to be 36cm²
Analysis
Let L be the length of each side of the square, a square has equal side.
Area of square is give as L²
Area=L²
L²=36
i.e L=√36
L=6cm
Therefore at t=0 L=6cm and A=36cm²
A=L²
dA/dL=2L
Given that, dL/dt=7
Multiply the two differential together
dA/dt= dA/dL × dL/dt
dA/dt= 2L × 7
dA/dt= 2×6×7
dA/dt= 84cm²/s
The rate of increase of the square is 84cm²/s
1.867 is the answer unless you need to round up more.
Answer:
Confidence interval @ 90% = [0.5324 < p < 0.5656]
Step-by-step explanation:
We are given the following information:
Sample size (n) = 2430
Proportion of win (p) = 0.549
Proportion of loss (q) => 1-p = 0.451
By formula of confidence interval,
CI = p ± Z(90%) * 
,
CI = 0.549±(1.645* ((0.549*(0.451))/2430))^(0.5)
CI = [0.5324 < p < 0.5656]
Write each equation in y = mx + b form so that you can compare the slopes.
Perpendicular slopes are opposite reciprocals.
For example: 2/3 and - 3/2; 4/5 and -5/4; 1/2 and -2
I. y = -3x + 2 m = -3
II. y = 3/2 x + 1/2 m = 3/2
III. y = - 1/3x + 1/3 m = -1/3
IV. y = 1/3x + 9 m = 1/3 (I assuming this one had a typo in it since there is no equal sign.)
LETTER B is the answer I & IV
