Draw a right angled triangle ABC, where <B = 90 degrees
<span>BC is the base, and BC = 12 m and C represents spot light on the ground and B is foot of the wall </span>
<span>Draw a perpendicular DE from a point D on hypotenuse, AC to a point E on BC </span>
<span>DE represents walking man and DE = 2 m </span>
<span>Now AB represents height of shadow, let AB = y </span>
<span>let EC = x </span>
<span>from similar triangles, ABC and DEC </span>
<span>AB/DE = BC/EC </span>
<span>y/2 = 12/x </span>
<span>y = 24/x </span>
<span>differentiating with respect to t </span>
<span>dy/dt = - (24/x^2) dx/dt </span>
<span>substitute x = (12 - 4) = 8 and dx/dt = 1.9 m/s </span>
<span>dy/dt = - (24 / 64)(1.9) </span>
<span>= -0.7125 </span>
<span>length of shadow is decreasing at the rate of 0.7125 m /s</span>
Answer:
x=4
Step-by-step explanation:
16/4=4
x=4
The solution for this problem is:
dV/dt = r/(t + 1)², V(0) = $500000, V(1) = $500000 - $200000 = $300000
∫dV = r∫ 1/(t + 1)² dt
V(t) = -r/(t + 1) + C
500000 = -r/(0 + 1) + C
400000 = -r/(1 + 1) + C
C = 300000, r = -100000
V(t) = 100000/(t + 1) + 300000
V(6) = 100000/(6+ 1) + 300000
V(6) = 14285.7143 + 300000
V(6) = $314285.71
Here are the steps
put it into y=mx+b 4y=-5x+20
to isolate y divide both sides by y=-5/4+5
to find the xi
xi is when y=0 so plug it in to the equation 4y=-5x+20 4(0)=-5x+20
0=-5x+20 subtract 20 from each side -20=-5x the negatives cancel out 20=5x
to isolate x divide each side by 5 x=20/5
20/5=4
Answers:
m=-5/4
yi=5
xi=4
Answer:
12 cm
Step-by-step explanation:
6 cm because 90 divided by 15 is 6 and 6 times 2 is 12
