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Alenkinab [10]
3 years ago
7

The perimeter of a triangle is 60cm,and the ratio of the measures of the side is 2:6:7. find the measures of each side?

Mathematics
2 answers:
Nitella [24]3 years ago
8 0
Hey!

Perimeter=60cm

Let sides be 'x'

Side 1=2x
Side 2=6x
Side 3=7x


Permiter of a triangle= s1+s2+s3 (sum of all sides)

60=2x+6x+7x
60=15x
60/15=x
x=4

Side 1= 2×4=8cm
Side 2=6×4=24cm
Side 3=7×4=28cm

Hope it helps...!!!

Kitty [74]3 years ago
3 0
The lengths are 8 cm, 24 cm, and 28 cm. Hope it helps!
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8 0
1 year ago
X2y4(x2 - 16) - 9y4(x4 - 16) how do i simply this?
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Answer:

The simplified expression is given as

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Step-by-step explanation:

step one:

Given the expression

x^2y^4(x^2 - 16) - 9y^4(x^4 - 16)

step two:

First, let us open the bracket we have

x^2y^4(x^2 - 16) - 9y^4(x^4 - 16)\\\\x^4y^4-16x^2y^4-9x^4y^4+144x^4y^4\\\\

step three:

collect like terms we have

x^4y^4-16x^2y^4-9x^4y^4+144x^4y^4\\\\x^4y^4-9x^4y^4+144x^4y^4-16x^2y^4\\\\-8x^4y^4+144x^4y^4-16x^2y^4\\\\136x^4y^4-16x^2y^4\\\\\\

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we can now factor out 8x^2y^4we have

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3 years ago
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Step-by-step explanation:

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2 years ago
Anyone know the answer to this?
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2 years ago
Roman numeral xxiii
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