All categories

2 years ago

The perimeter of a triangle is 60cm,and the ratio of the measures of the side is 2:6:7. find the measures of each side?

2 answers:

8 0

Hey!

Perimeter=60cm

Let sides be 'x'

Side 1=2x
Side 2=6x
Side 3=7x

Permiter of a triangle= s1+s2+s3 (sum of all sides)

60=2x+6x+7x
60=15x
60/15=x
x=4

Side 1= 2×4=8cm
Side 2=6×4=24cm
Side 3=7×4=28cm

Hope it helps...!!!

Kitty [74]2 years ago

3 0

The lengths are 8 cm, 24 cm, and 28 cm. Hope it helps!

You might be interested in

How do you do this?<br>-14 + 6b + 7 - 2b= 1 + 5b

lys-0071 [83]

-14 + 6b + 7 - 2b= 1 + 5b

combine like terms

-7 +4b = 1 + 5b

subtract 4b from each side

-7 + 4b -4b = 1 + 5b -4b

-7 = 1 + b

subtract 1 from each side

-7 -1 = 1-1 + b

-8 = b

8 0

2 years ago

Identify the scale factor when we scale up from Figure S to T. Just write the number.

Sergeu [11.5K]

Answer:

Scale factor = 4

Step-by-step explanation:

Scale factor = $\frac{\text{Dimension of the image}}{\text{Dimension of preimage or original}}$

Since, S is being dilated with a scale factor to form T,

So, the figure S is the preimage and figure T will be the image,

Length of one side of image T = 8

Length of one side of preimage = 2

Therefore, Scale factor = $\frac{8}{2}$

= 4

Scale factor by which figure S has been dilated to form figure T is 4.

3 0

2 years ago

How to represent 57.036 using fractions

egoroff_w [7]

$57.\underbrace{036}_{3}=\dfrac{57036}{1\underbrace{000}_{3}}=\dfrac{57036:4}{1000:4}=\dfrac{14259}{250}$

6 0

2 years ago

Given the functions, fx) = x - 8 and g(x) = x2 + x - 1, perform the indicated operation. When applicable, state the domain

adell [148]

Answer:

Step-by-step explanation:

(fg)(x) = f(x) × g(x)

= (x - 8)(x² + x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis

= x³ + x² - x - 8x² - 8x + 8 ← collect like terms

= x³ - 7x² - 9x + 8 → A

There are no restrictions on the domain.

4 0

3 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago