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Vladimir [108]
3 years ago
15

Which of the following are the equations for the parent function and the transformed parent function represented by the graph?

Mathematics
1 answer:
boyakko [2]3 years ago
3 0

Answer:

Parent function: y=\frac{1}{x}

Transformed function: y=-\frac{1}{x}

Step-by-step explanation:

The given function is a rational function.

The parent rational function is f(x)=\frac{1}{x}.

This is a hyperbola that is found in the first and third quadrant that is asymptotic to the axes.

The transformed function is a a hyperbola that is asymptotic to the axes and it is located in the second and fourth quadrant.

The point (1,1) on the parent function corresponds to (-1,1) on the transformed function.

The point (-1,-1) on the parent function corresponds to (1,-1) on the transformed function.

We can observe that the x-coordinates were negated in each case.

This the rule for a reflection in the y-axis.

Therefore the transformed function has equation g(x)=-\frac{1}{x}

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X^2+ 3x = 18 using zero product property
xz_007 [3.2K]
Its 18 to the 0 so one
8 0
3 years ago
A box of oat cereal costs $3.90 for 15 ounces. A box of rice of cereal costs $3.30 for 11 ounces. Which box of cereal costs less
Firlakuza [10]

Answer:

The cost of per ounce of oat cereal is $0.04 less than per ounce cost of rice.

Step-by-step explanation:

Given:

Cost of 15 ounces of oat cereal box = $3.90

Cost of 11 ounces of rice box = $3.30

To compare the unit prices of the the boxes.

Solution:

Using unitary method to find the unit prices:

If 15 ounce of oat box cost =$3.90

∴ 1 ounce of oat cereal would cost = \$\frac{3.90}{15}=\$0.26

∴ Per ounce cost of oat cereal = $0.26

If 11 ounce of rice box cost =$3.30

∴ 1 ounce of rice would cost = \$\frac{3.30}{11}=\$0.3

∴ Per ounce cost of rice = $0.3

Difference in unit costs of oat and rice = \$0.3-\$0.26=\$0.04

On comparing the the unit costs of oats and rice, we find out that the cost of per ounce of oat cereal is $0.04 less than per ounce cost of rice.

3 0
3 years ago
Solve for m.<br> 22m^2 + 7m - 2 = 0
pshichka [43]

Answer:

x= -1/2 and x=2/11

Step-by-step explanation:

Write the 7x as a difference. It'll make it easier to factor out. An example of this would be 11x-4x

Therefore, the equation would look like this: 22x^2 + 11x-4x -2 =0

Look at it as if there are two equations: 22x^2+11x and -4x-2

Factor out the greatest common factor, which is 11 from the first equation. The equation will then look like this: 11x(2x+1)

Take the GCF for the second equation as well (which is -2). The equation should then also look like this: (2x+1)

Use the numbers on the outside of each of the parenthesis to form its own equation (to factor it out). This will be 11x-2

Now we have factored! Since the parenthesis equations are the same, we know that that is also part of the equation, so:

(11x-2)(2x+1)

Solve each equation for x by equaling them both to zero

5 0
3 years ago
Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.
Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

y=ax^2+bx+c

Here the vertex of an up - down facing parabola has a form of,

x_v=-\dfrac{b}{2a}

The parameters we have are,

a=-5,b=-10, c=6

Plug them in vertex formula,

x_v=-\dfrac{-10}{2(-5)}=-1

Plug in the x_v into the equation,

y_v=-5(-1)^2-10(-1)+6=11

We now got a point parabola vertex with coordinates,

(x_v, y_v)\Longrightarrow(-1,11)

From here we emerge two rules:

  • If a then vertex is max value
  • If a>0 then vertex is min value

So our vertex is minimum value since,

a=-5\Longleftrightarrow a

Hope this helps.

r3t40

7 0
3 years ago
17. Which of the following equations would graph a line parallel to 3y = x + 5? (
Naddik [55]

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st

Step-by-step explanation:

Parallel lines have same slopes and different y-intercepts

To find which equation would graph a line parallel to 3y = x + 5

1. Put the equation in the form of y = mx + c

2. m is the slope of the line and c is the y-intercept

3. Look for the equation which has the same values of m and different

   values of c

∵ 3y = x + 5

- Divide each term of the equation by 3 to put the equation in the

 form of y = mx + c

∴ y = \frac{1}{3} x + \frac{5}{3}

∴ m = \frac{1}{3}

∴ c = \frac{5}{3}

The first answer:

∵ 3y = x + 1

- Divide each term of the equation by 3

∴ y = \frac{1}{3} x + \frac{1}{3}

∴ m = \frac{1}{3}

∴ c = \frac{1}{3}

∵ The two equations have same slope m = \frac{1}{3}

∵ The two equations have different y-intercepts c = \frac{5}{3}

   and c = \frac{1}{3}

∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5

Learn more:

You can learn more about slope of a line in brainly.com/question/12954015

#LearnwithBrainly

8 0
3 years ago
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