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Murrr4er [49]
2 years ago
12

What is the area of the figure?

Mathematics
1 answer:
Vitek1552 [10]2 years ago
3 0

Answer:

theres nothing there

Step-by-step explanation:

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Solve by completing the square? Could you please work it out step-by-step?
DaniilM [7]
16 n^2 -10n + 129 = 8n^2 -8

We collect the terms:
8n^2 -10n + 137 = 0

The steps for completing the square:

1) Move the "non X" (or "non N") term to the right:

8n^2 -10n  = -137

<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125 </span>

3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
-1.2 / 2 = -.6
-.6^2 = .36

</span>
n^2 -1.2n +.36 = <span>-17.125 +.36

Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root( <span> <span> <span> -16.765 </span> </span> </span> )
That's about as far as I can go.

4 0
3 years ago
I know I haven't been on this app for a long time but can ya'll help me plzz
nexus9112 [7]

Answer:

2774

Step-by-step explanation:

5 0
2 years ago
Please help asap
USPshnik [31]

C!!!!!!!!!!!!!!!!!!!!!!!!!

6 0
3 years ago
I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!
frutty [35]

Answer:

17) x=8

18) x=\sqrt{189} or x= 3\sqrt{21}

Step-by-step explanation:

So the rule is a^{2} +b^{2} =c^{2}, "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

                                               x^{2} +x^{2} =(8\sqrt{2})  ^{2}

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)    

                                                2x^2=8^2(\sqrt{2} )^{2}  

                                                  2x^2=64(2)

                                                   2x^2=128    

                                                  x^{2}= 128/2  

                                                     x^{2} =64

                                                        x=8      

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

                                                    c^{2} - b^{2} = a^{2}

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

                                                   15^{2} -6^{2} =x^{2}

                                                   225-36=x^{2}  

                                                     x^{2} =189

                                               x=\sqrt{189}=3\sqrt{21}

        The more you do these, the easier they'll get, so don't worry!

                           

4 0
3 years ago
Write the number in different ways
mina [271]
4. 15 tens, 1 hundred, 5 tens
150
5. 18 tens, 1 hundred, 8 tens
180


note: I hope this helps. I haven't done this in a long time. Sorry X(
3 0
2 years ago
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