3x - 2y = 10
10x + 2y = 8 (everything *2)
minus
Therefore final equation is -7x = 2 B
You can solve this in 2 easy steps: 1, multiply 44.55 by .17 (44.55 * .17 = 7.57) then adding the number you get to 44.55 (44.55 + 7.57 = 52.12). Your answer is D.
Given the number of the people attending the football game, the percentage supporters for the home team is 37%.
<h3>What is Percentage?</h3>
Percentage is simply number or ratio expressed as a fraction of 100.
It is expressed as;
Percentage = ( Part / Whole ) × 100%
Given the data in the question;
- Number of home team supporters nH = 1369
- Number of visting team supporters nV = 2331
- Percentage of supporters for home team PH = ?
For we determine the total number of people attending the football game;
nT = nH + nV
nT = 1369 + 2331
nT = 3700
Now, using the perecentage formula above, we find the Percentage of supporters for home team PH
Percentage = ( Part / Whole ) × 100%
PH = ( nH/ nT) × 100%
PH = ( 1369/ 3700) × 100%
PH = 0.37 × 100%
PH = 37%
Therefore, given the number of the people attending the football game, the percentage supporters for the home team is 37%.
Learn more about Percentages here: brainly.com/question/24159063
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The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
19.2 is 24% of 80 when i did the work
