If c is a real number and if 2+i is a solution of the equation x^2-4x+c, what is the value of c
1 answer:
2nd degree with real coefients
so if a+bi is a root then a-bi is also a root
if 2+i is a root then 2-i is also a root
so, the factored form of a quadratic equation with roots r1 and r2 is
(x-r1)(x-r2)
so
2+i and 2-i
(x-(2+i))(x-(2-i))
(x-2-i)(x-2+i)
expanding we get
x²-4x+5
so c=5
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Answer:
12(-3x + 2)
Step-by-step explanation:
-1/2 ( 32x - 40) - (20x - 4) = -16x + 20 - 20x + 4 = -36x + 24 = 6(-6x + 4) = 12(-3x + 2)
Answer:
Step-by-step explanation:
3
F (x)=y
y=2x-9
X Y
-2 -15 y=2 (-2)-9
y=-4+-9
y=-15
-1 -11 y=2 (-1)-9
y=-2+-9
y=-11
0 -9 y=2 (0)-9
y=0+-9
y=-9
1 -7 y=2 (1)-9
y=2+-9
y=-1
2 -5 y=2 (2)-9
y=4+-9
y=-5
Here is all the work
The answer is P=6 by simply isolating the p
Step-by-step explanation:
Simplified: ac - ab = d
c= (d+ab) * a
I believe!
Cheers!