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puteri [66]
4 years ago
13

Which expression is equivalent to (5x + 2) + (4.x - 3)?

Mathematics
1 answer:
Naddik [55]4 years ago
3 0

Answer:

Step-by-step explanation:

3

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5 0
3 years ago
(3/5)^2+4X3-2 what is the value of the expression
Sliva [168]

Answer:

10.36

Step-by-step explanation:

So your solution would be:

(\frac{3}{5})^{2} + 4 \times 3 - 2

=(\frac{3}{5})^{2} + 4 \times 3 - 2

=\dfrac{3^{2}}{5^{2}} + 4 \times 3 - 2

=\dfrac{9}{25} + 4 \times 3 - 2

=0.36 + 4 \times 3 - 2

=0.36 + 12 - 2

=12.36 - 2

=10.36

Just try to remember PEMDAS.

Parenthesis, Exponent, Multiplication/Division, Addition/Subtraction.

This is the order we follow when going about expressions with many operations.

Let's start with the parenthesis part. Notice that there is an exponent beside the parenthesis enclosing the fraction. Here we use the quotient to a power rule. We distribute the exponent to the numerator and the denominator.

=(\frac{3}{5})^{2} + 4 \times 3 - 2\\

=\dfrac{3^{2}}{5^{2}} + 4 \times 3 - 2

=\dfrac{9}{25} + 4 \times 3 - 2

Now that we got the parenthesis and exponent out of the way, let's move on to the next. Multiplication/Division. Whichever comes first, you do it first.

We have a fraction so we do that first. Then we do the multiplication after.

=0.36 + 4 \times 3 - 2

=0.36 + 12 - 2

Next we do the addition/subtraction. Again, whichever comes first.

=12.36 - 2

=10.36

7 0
4 years ago
Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
lina2011 [118]

Answer: Hewo, there! your answer is Below

a 90 clockwise rotation about the origin and a reflection over the y-axis

Step-by-step explanation:

Hope this helps you !!!

Have a great day!!!

3 0
3 years ago
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Answer:

what do u need help with lol

Step-by-step explanation:

7 0
2 years ago
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How do you do this problem 7-r=8-r-r​
Oliga [24]

Answer:

r = 1

Step-by-step explanation:

Solve for  r

by simplifying both sides of the equation, then isolating the variable.

3 0
3 years ago
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