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puteri [66]
3 years ago
13

Which expression is equivalent to (5x + 2) + (4.x - 3)?

Mathematics
1 answer:
Naddik [55]3 years ago
3 0

Answer:

Step-by-step explanation:

3

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The question is a image pls answer this​
Degger [83]

Answer:

Shade in the following boxes: 24, -9.0, 1, 0, and 35

Step-by-step explanation:

Integers are whole numbers (not fractions or decimals) that can be positive or negative.

8 0
2 years ago
(10p+96)+(-6p+93)=(9+75)
wariber [46]

Answer:-26.25

Step-by-step explanation:

6 0
3 years ago
Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
3 years ago
Are parallel lines inconsistent
Gelneren [198K]
If a consistent system has an infinite number of solutions, it is dependent. When you graph the equations, both equations represent the same line. <span>If a system has no solution, it is said to be </span>inconsistent. <span>The graphs of the </span>lines<span> do not intersect, so the graphs </span>are parallel<span> and there is no solution.</span>
5 0
3 years ago
Plzzz HELP will give brainliest 9^-53*9^37
slamgirl [31]

Answer: The exact form is 5.3965953e-16. But in exponential form: 9^(-16).

Step-by-step explanation:

Use your calculator to plug in the negative powers and to multiply. Do it one step at a time. If you want exponential form, then here:

9^(-53) * 9^(37)

Add exponents keep base

9^(-16)

Hope this helps

3 0
3 years ago
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