5
reason is because if you’re pentagon has lines of 5 then the area would be 25
Answer:
b = -2c ± [√(4π²c² + πA)]/π
Step-by-step explanation:
A = 4πbc + πb^2
A = 4πbc + πb²
πb² + 4πbc - A = 0
Using the quadratic formula to solve this quadratic equation.
The quadratic formula for the quadratic equation, pb² + qb + r = 0, is given as
b = [-q ± √(q² - 4pr)] ÷ 2p
Comparing
πb² + 4πbc - A = 0 with pb² + qb + r = 0,
p = π
q = 4πc
r = -A
b = [-q ± √(q² - 4pr)] ÷ 2p
b = {-4πc ± √[(4πc)² - 4(π)(-A)]} ÷ 2π
b = {-4πc ± √[16π²c² + 4πA]} ÷ 2π
b = (-4πc/2π) ± {√[16π²c² + 4πA] ÷ 2π}
b = -2c ± [√(4π²c² + πA)]/π
Hope this Helps!!!
Answers:
Horizontal Line: y = 5
Vertical Line: x = 8
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Explanation:
All horizontal lines are of the form y = k, for some constant k. We want the horizontal line to pass through (8,5), meaning every point on this horizontal line must have y coordinate 5. Therefore, y = 5 is the equation of the horizontal line. Two such points on this line are (1, 5) and (8, 5). All that matters is the y coordinate is 5. The x coordinate can be anything you want. The slope of any horizontal line is 0.
Flipping things around, all vertical lines will have the x coordinate of each point be the same value. Draw a vertical line through (8,5) and note how each point has x coordinate of 8. Two such points are (8,1) and (8,5). Therefore, the equation of the vertical line is x = 8. The y coordinate can be any value you want. The slope of any vertical line is undefined. Unlike the horizontal line, we cannot write this equation in slope intercept form (namely because the slope isn't defined).
True ........... I Hope this helps you answer your question.
Part A: 1 7/9
Part B: ????
Sorry I don't get it
