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2 years ago

Alice has 15 times as many crayons as Bryan. Write an equation to find the total number of crayons that Alice has.

Mathematics

1 answer:

vichka [17]2 years ago

6 0

Answer:

a = 15b

Step-by-step explanation:

It's given in the question that Alice has 15 times as many crayons as Bryan.

Let the number of crayons with Bryan = b

And the number of crayons with Alice = a

Therefore, equation representing the number of crayons with Alice will be,

a = 15b

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B. Distinct Parallel lines.

Step-by-step explanation:

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2 years ago

Select all of the potential solution(s) of the equation 2log5x = log54.

Vanyuwa [196]

Answer:

x = ±2

Step-by-step explanation:

A equation is given to us , which is ,

$\longrightarrow 2log_5(x) = log_5 4$

From properties of logarithm we know that ,

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Applying this to LHS , we have ;

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Now the bases of logarithm on LHS and RHS is same . On comparing , we have ;

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2 years ago

QUESTION 1

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It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let θ be the angle between the force vector F and the displacement vector r. The work W done by F in the direction of r is

W = F • r cos(θ)

The cosine of the angle between the vectors can be obtained from the dot product identity,

a • b = ||a|| ||b|| cos(θ) ==> cos(θ) = (a • b) / (||a|| ||b||)

so that

W = (F • r)² / (||F|| ||r||)

For instance, if F = 3i + j + k and r = 7i - 7j - k (which is my closest guess to the given vectors' components), then the work done by F along r is

W = ((3i + j + k) • (7i - 7j - k))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

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Answer:

slope is m=2

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divided by

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3 years ago

Without further study, you forget things as time passes. A model of human memory gives the percentage, p, of acquired knowledge

PIT_PIT [208]

Answer:

42.69% of information is acquired by the student in two weeks.

Step-by-step explanation:

We are given the following in the question:

$p = (100 -a)e^{-bt} + a$

where a and b are constants.

$a = 18\\b = 0.6$

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We put t = 2

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Thus, 42.69% of information is acquired by the student in two weeks.

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