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Llana [10]
3 years ago
10

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT

Mathematics
1 answer:
Alla [95]3 years ago
8 0
5
4
2
3
1 hope this helps now mark me brainliest
You might be interested in
What's 14/63 in simplest form
serious [3.7K]
You would cancel the common factors in the numerator and denominator. 

Exact Form: 
2/9 

Decimal Form: 
0.222222222.....
8 0
3 years ago
Steve can run 3.5 miles in 30 minutes. If Steve increases his rate by 1/2 mile per hour, how far will he run in 2 hours?
Sati [7]

Answer:

15 miles

Step-by-step explanation:

Steve runs 3.5 miles in 30 minutes (0.5 hours).  So his speed is:

r = 3.5 mi / 0.5 h

r = 7 mi/h

If his rate increases to 7.5 mi/h, the distance he runs in 2 hours is:

d = 7.5 mi/h × 2 h

d = 15 mi

7 0
3 years ago
Read 2 more answers
the distance from Gracie's school to the corner market is 47 yds the distance to die what station is 12 times as far how far is
fenix001 [56]
It is 21 miles because 9+10 =21
4 0
3 years ago
See attached image. Thanks!
madam [21]

Answer:

17

Step-by-step explanation:

n(Band and Choir only)

= 25 - 11 - 7 - 3 = 4

n(Math and Band only)

= 7

n(Math and Choir only)

= 57 - (25 + 17 + 9)

= 6

Exactly 2:

4 + 7 + 6

= 17

6 0
4 years ago
Solve one of the following two non-homogeneous differential equations using whatever technique your prefer. Put an "X" through t
noname [10]

Answer:

a.y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

by(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

Step-by-step explanation:

1.y''-4y'+4y=6x e^{2x}

Auxillary equation

D^2-4D+ 4=0

(D-2)(D-2)=0

D=2,2

Then complementary solution =C_1e^{2x}+C_2xe^{2x}

Particular solution =\frac{6 xe^{2x}}{(D-2)^2}

D is replace by D+2 then we get

P.I=\frac{6xe^{2x}}{0}

P.I=\frac{e^{ax}}{D+a} \cdot .V

where V is a function of x

P.I=\frac}x^3e^{2x}

By integrating two times

Hence, the general solution

y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

b.y''+9y=5 cos x-7 sin x

Auxillary equation

D^2+9=0

D=\pm 3i

C.F=c_1 cos 3x+ c_2sin 3x

P.I=\frac{5 cos x-7 sin x}{D^2+9}

P.I=\frac{sin ax}{D^2+bD +C}

Then  D square is replace by -a square

D^2 is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

4 0
3 years ago
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