Answer:


Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:

Multiply by 2y+9

Simplify:

Operate the parentheses:


Subtract 3y and
:

Factor y out of the left side:

Divide by
:

ii) To find y when x=2, substitute:





Answer:
hi there! i can help you out! i don't want you to get a zero on your report card!!
Step-by-step explanation:
so, on the x-axis, which is all the numbers through 1-10 and there are the patient's number. so for ex, the first question says patient 1 : 3 hours right??
so the hours are the y-axis and you can label them 2,4,6,8 because skip counting by twos are probably the easiest! so for the first question, you would line a dot up on top of 1 and go up and you see 2 and 4 right, cuz you just labeled it... do go between 2 and 4 which is 3 and place the dot there...
and keep doing the same things with other ones too...
another ex! so on the second question, it says patient 2 : 7 hours so place the dot on top of the 2 and go up untill you see 6 and 8 and place the dot beween them!
Barry will use the distance formula:
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
d = √[(4 - 3)² + (7 - 1)²]
d = 6.08 units