Answer:
mDF = 90°
(Assuming arc mCE is 5x + 10)
Step-by-step explanation:
When we have two chords crossing in a circle, there is a property where the angle in the cross point is equal half the sum of the corresponding arcs.
So in this case, we have:
70° = (mCE + mDF)/2
Assuming mCE is 5x + 10, we have:
70 = (5x + 10 + 11x + 2)/2
70 = (16x + 12)/2
70 = 8x + 6
8x = 64
x = 8
So the arc mDF is:
mDF = 11x + 2 = 11 * 8 + 2 = 90°
Answer:
A) 10-20
Step-by-step explanation:
Its A because it started with 0 and it went to 10 so it adds 10 each time cause it gave us the hint with 0 to 10,
I hope this helps
Answer:
The equation of the line that is <em>perpendicular</em> to <em>y = 2x + 2</em> is
<em>y = -1/2x</em>
Step-by-step explanation:
The original equation is y = 2x + 2; it's slope is <em>2</em>
Any line perpendicular to this equation would have to have a slope that is the negative reciprocal of the original slope.
Example:
y = 2x + 2 so,
the perpendicular line's slope must be -1/2
Write a new equation with the new slope:
y = -1/2x + b
We know that this line passes through (8, -4)
Plug these coordinates in the equation to find b, the y-intercept
-4 = -1/2 (8) + b
-4 = -4 + b
0 = b
b = 0
We do not have to write y = -1/2x + 0
So, our final answer is "y = -1/2x is perpendicular to y = 2x+2"
Answer:
Saw this question before. The answer is Anita' square.
Square has only four sides while the others more than four so make sense for the square to have longer sides
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614