Answer:
_ = 5
Step-by-step explanation:
Answer:
The probability that the intersection will come under the emergency program is 0.1587.
Step-by-step explanation:
Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.
Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.
For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.
Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).

The values of
, the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program

Answer:
slope = 0
Step-by-step explanation:
point1 = (0,7)
point 2 =(7,7)
slope = (y2-y1)/(x2-x1) => (7-7)/(7-0)
slope = 0
Answer:

Step-by-step explanation:
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<span>If the nemesis has "7/8 of her cats plus 2" it can be written like this: 7/8 x + 2 = x, where x is the number of the cats. After that we can solve the equation. x - 7/8 x = 2; 1/8 x = 2; x = 2 : 1/8 = 2 * 8 = 16. Answer: The nemesis has 16 cats.</span>