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4 years ago

Subtract 350 Ib from 4 tons

Mathematics

2 answers:

tiny-mole [99]4 years ago

7 0

7, 450 lbs is the answer

CaHeK987 [17]4 years ago

4 0

Answer:

I got 7,650.

Step-by-step explanation:

each ton is 2,000 pounds, and there is 4.

so 8,000 -350=7,650

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An ordered pair is written as:

faust18 [17]

An ordered pair is written as (x, y).

For example:

(4, 5)
(8, 10)
(10293102398102398, 234587204398769035287)
(zebra, giraffe)
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3 0

4 years ago

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How many solutions does the system have?2y=4x+6 y=2x+6

Maksim231197 [3]

Answer:

there is no solutions.

Step-by-step explanation:

replace y in 2y=4x+6 with 2x+6

2(2x+6)=4x+6

mulitply the terms

4x+12=4x+6

subtract 4x from both sides or the equal sign.

the answer is 12=6 which is not equal to each other

there's not solutions.

3 0

3 years ago

padilas [110]

Answer:

x = 31

ROS = 62

Step-by-step explanation:

QOR + ROS = 90 degrees as indicated by the box

28+ 2x = 90

Subtract 28 from each side

2x = 90 -28

2x = 62

Divide by 2

2x/2 = 62/2

x = 31

ROS = 2x = 2*31 = 62

7 0

3 years ago

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What can you conclude from a box plot where the length of the left box and whisker is the same as the length of the right box an

Norma-Jean [14]

Answer/Step-by-step explanation:

The length of the boxes and whiskers of a box plot tells us more about the spread the data being represented is and as well as the shape of the spread.

Invariably, if the length of the left box and left whiskers is of the same length as the right box and right whiskers, this implies that the distribution of the data point is close to being symmetric, or approximately symmetrical.

4 0

3 years ago

What is the sum of the geometric series

lbvjy [14]

If $S$ denotes the sum of the first $n$ terms of a geometric series with first term $a$ and common ratio $r$ , then

$S=a+ar+ar^2+\cdots+ar^{n-3}+ar^{n-2}+ar^{n-1}$
$rS=ar+ar^2+ar^3+\cdots+ar^{n-2}+ar^{n-1}+ar^n$
$\implies S-rS=a+(ar-ar)+(ar^2-ar^2)+\cdots+(ar^{n-1}-ar^{n-1})-ar^n$
$\implies (1-r)S=a(1-r^n)$
$\implies S=a=\dfrac{1-r^n}{1-r}$

Using summation notation, you have

$S=\displaystyle\sum_{x=1}^nar^{x-1}=\sum_{x=0}^{n-1}ar^x=a\dfrac{1-r^n}{1-r}$

In this case, you have $a=2$ , $r=\dfrac12$ , and $n=16$ . So the value of the sum is

$\displaystyle\sum_{x=0}^{15}2\left(\frac14\right)^x=2\dfrac{1-\left(\frac14\right)^{16}}{1-\frac14}\approx2.67$

Rounded to the nearest whole number, the answer would be 3.

4 0

4 years ago

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