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lubasha [3.4K]
3 years ago
15

The first three terms of a geometric sequence are shown below.

Mathematics
2 answers:
san4es73 [151]3 years ago
4 0
This is a geometric sequence of the form:

a(n)=(x+3)(-2x)^(n-1)  because each term is -2x times the previous term...so

a(8)=(x+3)(-128x^7)

a(8)=-128x^8-384x^7
Elis [28]3 years ago
4 0

Answer:

a_8=-128x^8-384x^{7}

Step-by-step explanation:

G.P. = x+3,-2x^2-6x,4x^3+12x^2+...

So, first term = a=x+3

Common ratio = r =\frac{a_2}{a_1}

                       = \frac{-2x^2-6x}{x+3}

                       = \frac{-2x(x+3)}{x+3}

                       = -2x

So, r = -2x

nth term of G.P. = a_n=ar^{n-1}

Substitute n = 8

a_8=(x+3)(-2x)^{8-1}

a_8=(x+3)(-2x)^{7}

a_8=(x+3)(-128)(x)^{7}

a_8=-128x^8-384x^{7}

Hence the eighth term of the sequence is  a_8=-128x^8-384x^{7}

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Answer:

89/5

Step-by-step explanation:

17.8

To make this a faction

178/10

Divide by 2 on top and bottom

89/5

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Step-by-step explanation:

We start with -8F as the temperature. It fell 10 degrees to 2F, then fell 8 degrees to -6F.

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sergejj [24]

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Correct

Step-by-step explanation:

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solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

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