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3 years ago

-5(n + 3) = 6(n +4) + 5

Mathematics

2 answers:

laiz [17]3 years ago

6 0

Answer:

n = -4

Step-by-step explanation:

−5(n+3)=6(n+4)+5

Step 1: Simplify both sides of the equation.

−5(n+3)=6(n+4)+5

(−5)(n)+(−5)(3)=(6)(n)+(6)(4)+5(Distribute)

−5n+−15=6n+24+5

−5n−15=(6n)+(24+5)(Combine Like Terms)

−5n−15=6n+29

Step 2: Subtract 6n from both sides.

−5n−15−6n=6n+29−6n

−11n−15=29

Step 3: Add 15 to both sides.

−11n−15+15=29+15

−11n=44

Step 4: Divide both sides by -11.

−11n

−11

n=−4

monitta3 years ago

3 0

Answer:

n = -4

Step-by-step explanation:

-5(n + 3) = 6(n +4) + 5

First distribute by multiplying:

-5(n + 3) = 6(n +4) + 5 into:

-5n-15=6n+24+5

Combine Like Terms (CLT):

-5n-15=6n+24+5

-5n-15=6n+29

Inverse operation:

-5n-15=6n+29

+15 +15

-5n=6n+44

-11n=44

_______

-11 -11

n = -4

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jonny [76]

Answer:

D) -1.8, -1 1/2 , 0.3 , 3/4 , 1

Step-by-step explanation:

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Order from least to greatest:

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5 0

3 years ago

Read 2 more answers

Q7Which statement is incorrect for the graph of thefunction y = -5 cosGcos( 3 (x – 3)) +62The period is 4.The amplitude is 3.The

guajiro [1.7K]

The given function is,

$y=-5\cos (\frac{\pi}{2}(x-3))+6$

The graph can be drawn as,

The period will be distance between two consequetive maximas,

$\text{Period}=1-(-3)=4$

Thus, period is correct.

The amplitude can be determined as,

$\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}$

Thus, amplitue is incorrect.

The range is,

$y\in\lbrack1,11\rbrack$

Thus, the range is correct.

The midline is,

$\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}$

Thus, the midline is correct.

Thus, option (b) is the solution.

5 0

1 year ago

Evaluate -2 with an exponent of 3

zheka24 [161]

When raised to the third power, it is the number times itself three times.

-2(-2) = 4

4(-2) = -8

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2 years ago

Read 2 more answers

saul85 [17]

Answer:

Step-by-step explanation:

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3 years ago

What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

Kitty [74]

Answer:

$-\frac{3p^8}{4q^3}$

Step-by-step explanation:

$\frac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}}$ can be broken down into three fractions, coefficients, powers of p, powers of q.

$-\frac{15}{20}\cdot\frac{p^{-4}}{p^{-12}}\cdot\frac{q^{-6}}{q^{-3}}$

Simplify the first fraction, then simplify the others by subtracting numerator exponents minus denominator exponents.

$-\frac{3}{4} p^{-4-(-12)} q^{-6-(-3)} =-\frac{3}{4} p^8 q^{-3} = \alpha -\frac{3p^8}{4q^3}$

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2 years ago