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nika2105 [10]
4 years ago
11

-5(n + 3) = 6(n +4) + 5

Mathematics
2 answers:
laiz [17]4 years ago
6 0

Answer:

n = -4

Step-by-step explanation:

−5(n+3)=6(n+4)+5

Step 1: Simplify both sides of the equation.

−5(n+3)=6(n+4)+5

(−5)(n)+(−5)(3)=(6)(n)+(6)(4)+5(Distribute)

−5n+−15=6n+24+5

−5n−15=(6n)+(24+5)(Combine Like Terms)

−5n−15=6n+29

−5n−15=6n+29

Step 2: Subtract 6n from both sides.

−5n−15−6n=6n+29−6n

−11n−15=29

Step 3: Add 15 to both sides.

−11n−15+15=29+15

−11n=44

Step 4: Divide both sides by -11.

−11n

−11

=

44

−11

n=−4

monitta4 years ago
3 0

Answer:

n = -4

Step-by-step explanation:

-5(n + 3) = 6(n +4) + 5

First distribute by multiplying:

-5(n + 3) = 6(n +4) + 5 into:

-5n-15=6n+24+5

Combine Like Terms (CLT):

-5n-15=6n+24+5

-5n-15=6n+29

Inverse operation:

-5n-15=6n+29

     +15     +15

-5n=6n+44

-11n=44

_______

-11     -11

n = -4

                 

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<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

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By using calculator, let's convert those numbers into decimal form:

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\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}

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Step-by-step explanation:

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If 180° &lt; α &lt; 270°, cos⁡ α = −817, 270° &lt; β &lt; 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?
eduard

Answer:

cos(\alpha+\beta)=-\frac{84}{85}

Step-by-step explanation:

we know that

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

Remember the identity

cos^{2} (x)+sin^2(x)=1

step 1

Find the value of sin(\alpha)

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

cos(\alpha)=-\frac{8}{17}

Find the value of sine

cos^{2} (\alpha)+sin^2(\alpha)=1

substitute

(-\frac{8}{17})^{2}+sin^2(\alpha)=1

sin^2(\alpha)=1-\frac{64}{289}

sin^2(\alpha)=\frac{225}{289}

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step 2

Find the value of cos(\beta)

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

sin(\beta)=-\frac{4}{5}

Find the value of cosine

cos^{2} (\beta)+sin^2(\beta)=1

substitute

(-\frac{4}{5})^{2}+cos^2(\beta)=1

cos^2(\beta)=1-\frac{16}{25}

cos^2(\beta)=\frac{9}{25}

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step 3

Find cos⁡ (α + β)

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

we have

cos(\alpha)=-\frac{8}{17}

sin(\alpha)=-\frac{15}{17}

sin(\beta)=-\frac{4}{5}

cos(\beta)=\frac{3}{5}

substitute

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cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}

cos(\alpha+\beta)=-\frac{84}{85}

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