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melamori03 [73]
4 years ago
13

Which statement describes the potential energy diagram of an endothermic reaction?

Chemistry
1 answer:
VMariaS [17]4 years ago
3 0

Answer: option C. The potential energy of the products is greater than the potential energy of the reactants.


Explanation:


1) The potential energy diagram shows the evolution of the potential chemical energy of a process or reaction, measured as energy of the chemical bonds, including the reactants, the intermediates, the activated complex, and the products.


The vertical axis is the potential energy (energy of the chemical bonds) of the substances, and the horizontal axis is time.


2) An endothermic reaction is that that absorbs energy from the surroundings to lead the substances to a higher chemical potential energy. The surroundings will get cooler and the products will content more potential energy than the reactants.


3) At the beginning, the potential energy is that of the reactants; as the reaction progress, the potential energy increase, since the particles (molecules, atoms or ions) have to reach the peak, which is the point where the activated complex has been formed. From that point, the potential energy starts to decrease until the final products are formed.


3) The energy of the final state (the products) will be higher than the energy of the initial state, if the reaction absorbed heat from the surroundings (which is what an endothermic reaction is). If the final energy is less than the initial one, the products have released energy and that is an exothermic reaction.


4) The curve (diagram) shows that, and the choice C indicates correctly the change in the energy for an endothermic reaction: The potential energy of the products is greater than the potential energy of the reactants.

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Suppose that a newly discovered element called centium has 3 isotopes that occure in nature. These are centium -200, centium -20
vodomira [7]

Answer:

The answer to your question is 203.8 g

Explanation:

Data

Average atomic mass = ?

Centium-200

Centium-203

Centium-209

Equal amounts

Process

1.- Determine the abundance of each isotope.

If they are in equal amounts in nature, just divide 100 by 3

             100/3 = 33.33 % or 0.333

2.- Determine the Average atomic mass

Average atomic mass = Atomic mass 1 x abundance + Atomic mass 2 x

                                        abundance + Atomic mass 3 x abundance

- Substitution

Average atomic mass = 200 x 0.333 + 203 x 0.333 + 209 x 0.333

- Simplification

Average atomic mass = 66.6 + 67.6 + 69.6

Result

Average atomic mass = 203.8 g

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3 years ago
Write the formula of salt produced in lithium + Sulfuric Acid equals to
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. The products are lithium sulfate, Li2SO4 , and water, H2O

Explanation:

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Answer:

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Explanation:

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If 24.3 g of NO and 13.8 g of O₂ are used to form NO₂, how many moles of excess reactant will be left over?2 NO (g) + O₂ (g) → 2
zhuklara [117]

Explanation:

2 NO (g) + O₂ (g) ----> 2 NO₂ (g)

24.3 g of NO are reacting with 13.8 g of O₂. First we can convert the mass of theses samples into moles using their molar masses.

molar mass of O = 16.00 g/mol

molar mass of N = 14.01 g/mol

molar mass of NO = 16.00 g/mol + 14.01 g/mol

molar mass of NO = 30.01 g/mol

molar mass of O₂ = 2 * 16.00 g/mol

molar mass of O₂ = 32.00 g/mol

moles of NO = 24.3 g * 1 mol/(30.01 g)

moles of NO = 0.810 moles

moles of O₂ = 13.8 g * 1 mol/(32.00 g)

moles of O₂ = 0.431 moles

Now, to determine the limiting reactant or the excess reactant we can find the number of moles of O₂ that will react with 0.810 moles of NO and the number of moles of NO that will react with 0.431 moles of O₂.

According to the coefficients of the reaction 2 moles of NO will react with 1 mol of O₂. Let's use that relationship to find the limiting reagent.

2 moles of NO = 1 mol of O₂

moles of O₂ = 0.810 moles of NO * 1 mol of O₂/(2 moles of NO)

moles of O₂ = 0.405 moles

moles of NO = 0.431 moles of O₂ * 2 moles of NO/(1 mol of O₂)

moles of NO = 0.862 moles

We found that we need 0.405 moles of O₂ to completely react with 0.810 moles of NO. Or, we need 0.862 moles of NO to completely react with ours 0.431 moles of NO.

We can say that NO is limiting our reaction and O₂ is in excess.

Only 0.405 moles of O₂ will react with 0.810 moles of NO. But we had 0.431 moles of it. Let's find the excess.

Excess of O₂ = 0.431 moles - 0.405 moles

Excess of O₂ = 0.026 moles

Answer: 0.026 moles is the number of moles of oxygen that will be left over.

4 0
1 year ago
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