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3 years ago

What is the difference between melting and melting point

Chemistry

1 answer:

Yakvenalex [24]3 years ago

4 0

Answer:

Melting Is when a substance is actually melting and melting point is a point at which a substance is able to melt.

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A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio

Zigmanuir [339]

Answer: The concentration of original sulfuric acid solution is 1.62 M

Explanation:

Let the original concentration of sulfuric acid be 'x' M

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated sulfuric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted sulfuric acid solution

We are given:

$M_1=xM\\V_1=25.00mL\\M_2=?M\\V_2=250.0mL$

Putting values in above equation, we get:

$x\times 25.00=M_2\times 250.0\\\\M_2=\frac{x\times 25.0}{250}=\frac{x}{10}$

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=\frac{x}{10}M\\V_1=10.00mL\\n_2=1\\M_2=0.1790M\\V_2=18.07mL$

Putting values in above equation, we get:

$2\times \frac{x}{10}\times 10.00=1\times 0.1790\times 18.07\\\\x=\frac{1\times 0.1790\times 18.07\times 10}{2\times 10.00}=1.62M$

Hence, the concentration of original sulfuric acid solution is 1.62 M

5 0

3 years ago

Pedro’s teacher wrote the formula for glucose, a common sugar, on the board. Pedro learned that the letters in the formula repre

sveta [45]

Answer:

Explanation:

Im not quite sure if its correct or not

8 0

2 years ago

How many grams of calcium hydroxide must react to give 3.09 g of Ca3(PO4)2?

emmainna [20.7K]

Molar mass:

Ca(OH)₂ = 74.093 g/mol
Ca₃(PO₄)₂ = 310.17 g/mol

Mole ratio:

2 Na₃PO₄ + 3 Ca(OH)₂ = Ca₃(PO₄)₂ + 6 NaOH

3 x 74.093 g Ca(OH)₂ ----------- 310.17 g Ca₃(PO₄)₂
?? g Ca(OH)₂ ----------- 3.09 g Ca₃(PO₄)₂

Mass of Ca(OH)₂ = 3.09 x 3 x 74.093 / 310.17

Mas of Ca(OH)₂ = 686.84211 / 310.17

= 2.214 g of Ca(OH)₂

hope this helps!

7 0

2 years ago

If you start with 5 molecules of O2 in the reaction 2Mg + O2 2 MgO, how much Mg will you need

hichkok12 [17]

2Mg + O₂ ---> 2MgO

2 atoms Mg --- 1 molecules O₂
X atoms Mg --- 5 molecules O₂
X = 2×5
X = 10 atoms Mg

4 0

3 years ago

What is the mass percentage of cobalt in cobalt(ii) fluoride, cof2?

ra1l [238]

I’m not sure about the whole compound but I know that Cobalt mass Percentage is 60.800%
And Fluorine is 39.200%.
I hope that helps a little!

7 0

3 years ago