Hopefully this will help you my friend.
In order to find out the number of electrons present in s orbital of Phosphorous we have to write the electronic configuration of phosphorous.
As the Atomic number of Phosphorous is 15 so it will have 15 electrons in neutral state. So,
P = 15 = 1s², 2s², 2p⁶, 3s², 3p³
Now analyzing electronic configuration, we found that it contains 3 s orbitals, i.e. 1s, 2s and 3s, and each s orbital is completely filled with two electrons each.
Result:
Therefore, a total of six electrons are present in all s orbitals of neutral Phosphorous Atom.
Answer:700 nm corresponded to light in the red range and 450 nm corresponded to light in the blue range.
Explanation:The wavelengths of the visible spectrum are usually between 400 nm and 700 nmn with the the rays of red light having a longer wavelength, and blue light rays having shorter wavelengths. The red light has a low frequency of about 405–480 THz and , blue light has a higher frequency in the range of 620–680 THz. This is due to the inverse relationship between wavelength and frequency which also occurs betwwn wavelength and energy of light rays with the red light having less photon energy of about 1.65–2.00 eV and the blue light with high energy photons of about 2.64–2.75 eV.
Red light can be employed in the photosynthesis in plants as it helps in formation of flowers and the production of fruits. Blue light also is important in the production of chlorophyll and can cause a healthy and strong stem and leaves in excess exposure.
