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sammy [17]
3 years ago
5

Select all of the BENEFITS of a PARALLEL circuit. If one bulb burns out the rest of the bulbs will stay lit. The bulbs do not ge

t dimmer when we add more bulbs to the c The circuits are more complex and expensive. The circuits use less wire
Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

The first two options are correct

Explanation:

The first two options are part of the benefits of a parallel connection of bulbs in a circuit. Here, the voltage of each connecting bulb is the same as the voltage of the bulb in the circuit hence all the bulbs have the same voltage running through them. Thus, when one bulb is removed/burns out, it does not affect the remaining bulbs (those ones will remain lit). Also, the addition of bulb(s) does not cause the remaining bulbs in the circuit to get dimmer (since they will all have the same voltage).

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Given the reaction:
WARRIOR [948]

Answer:

4 moles

Explanation:

From the equation 1 mole of C6H1206 produces  6 moles of CO2.

Therefore  the answer is 24/6 = 4 moles of C6H1206.

6 0
3 years ago
How can a scientist make sure that the results are not a mistake in an experiment?
olga55 [171]
Repeat trials multiple times
8 0
3 years ago
If 585.24 Joules of heat are added to 53.2 grams of water at 24.15oC, what will the new temp. be?
spayn [35]
E = mct
Energy = (mass) x (specific heat capacity of water) x (change in temp)

585.24 = 53.2 x 4.2 x (X-24.15)


585.24 divided by 53.2 divided by 4.2 = X - 24.15

2.62 = X - 24.15

X= 26.77degrees C

(Specific heat capacity for water is 4.2 but is different for other liquids)
3 0
3 years ago
The standard internal energy change for a reaction can be symbolized as Δ U ∘ rxn or Δ E ∘ rxn . For each reaction equation, cal
rosijanka [135]

Answer : The internal energy change is, -506.3 kJ/mol

Explanation :

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -511.3kJ/mol=-511300.0J/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = 0 - 2 = -2 mole

That means, value of \Delta n_gRT = 0

R = gas constant = 8.314 J/mol.K

T = temperature = 25^oC=273+25=298K

Now put all the given values in the above formula, we get

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-511300.0J/mol)-[-2mol\times 8.314J/mol.K\times 298K

\Delta U=-511300.0J/mol+4955.144J/mol

\Delta U=-506344.856J/mol=-506.3kJ/mol

Therefore, the internal energy change is -506.3 kJ/mol

6 0
3 years ago
Write the balanced equation for the neutralization reaction between h2so4 with naoh
Sedaia [141]
H2SO4 or hydrogen sulfate is an acid and NaOH or sodium hydroxide is a base or an alkali. The reaction between an acid and a base or alkali produces a salt and water. The reaction between these substances is shown below:
H2SO4 (aq) + 2NaOH (aq)------>2H20 (L) + Na2SO4 (aq). The salt produced in this reaction is sodium sulfate. 
5 0
3 years ago
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