Answer:
B) their promoters have different affinities for RNA polymerase holoenzyme.
Explanation:
The housekeeping genes are the one whose products are involved in the vital metabolic pathways. So, these genes are mostly expressed at a constant level in the cells. However, the protein products of housekeeping genes exhibit variations in their cellular concentration.
The variation in the expression of housekeeping genes is regulated by the interaction between RNA polymerase holoenzyme and promoter.
The variations in the promoter sequences of these genes regulate the rate of the initiation of transcription by affecting the interaction between RNA polymerase-promoters. Certain promoter sequences facilitate the binding of RNA polymerase more than the other ones. This differential interaction regulates the rate of transcription initiation and accounts for variable cellular concentration of products of housekeeping genes.
Your answer is........C. Speed
1. Is the child is born male then the then the probability is 50%, and if female then the child will be normal provided father is normal.
2. Probability of me receiving the affected gene is 50%.
3. If the mother is normal then 0% chance that the child will receive mutated allele in his genome.
<h3><u>Explanation:</u></h3>
Duchenne muscular dystrophy is sex linked recessive disease which is seen as hereditary disease. This disease has a mutated gene which is present on the X chromosome. It produces proteins that results in muscular dystrophy.
A. As the mother's brother is affected with the disease so we can assume that the mother is a carrier of this disease. Hence one of the X chromosomes of mother is affected. If the child is female then 1 X chromosome will be received from father and other one from mother. So if the father is normal then even if the child receives mutated X chromosome from mother then also she will be normal. So a female child want to be a diseased one if the father is normal. If the child is male then and there is a 50% chance that the X chromosome he is receiving from mother is the mutated one. Show the chance of child being diseased is 50%.
B. As the mother's brother is deceased then the mother is taken to be a carrier. Hence one of the X chromosomes of mother is mutated and other one is normal. Hence the chance of receiving the mutated allele from mother is becomes 50%.
C. As the father's brother is having disease but father is not having the disease then fathers X chromosome must be normal because if the mutated allele was present then father would have been diseased as well. Hence is the mother is normal then the chance of the child being diseased becomes 0% .
It is the macroscopic anatomy with a systemic approach.
There are two levels of the human body: macroscopic (gross anatomy) and microscopic level. For each of the two levels, there is a separate subdivision of anatomy.
There are two approaches for gross anatomy:
1. Regional approach-human body is divided into regions like arm, forearm, wrist etc. Structures within that region are studied simultaneously.
<span>2. Systemic approach-the body is divided into organ systems like skeletal system, or nervous system and structures belonging to one system are studied together.</span>