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3 years ago

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A candy company advertises that 3 out of 24 of its chocolate candy bars contain a prize. Based on this information, how many cho

colate candy bars out of 120 should contain a prize?

1 answer:

alina1380 [7]3 years ago

8 0

The answer is 15 because 24x5 =120 so 3x5 =15

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The scatterplot shows the average number of hours each of 12 people spends at work every week and the average number of hours ea

babunello [35]

Answer: 22

Step-by-step explanation: I took the test

5 0

3 years ago

Read 2 more answers

A clothing company sells slacks that are either blue or gray and pleated or non-pleated. Last month, the company sold 5 times as

qwelly [4]

Answer:

138 pairs

Step-by-step explanation:

The number of blue pleated slacks is 5 times the number of gray pleated slacks, so:

$blue\ pleated = 5 * gray\ pleated$ (eq1)

The number of gray non-pleated is twice the number of blue non-pleated slacks, so:

$blue\ nonpleated = 2 * gray\ nonpleated$ (eq2)

The total number of blue slacks is 333, and the total number of gray slacks is 225, so we have that:

$blue\ pleated + blue\ nonpleated = 333$ (eq3)

$gray\ pleated + gray\ nonpleated = 225$ (eq4)

If we add (eq1) and (eq2), we have:

$blue\ pleated + blue\ nonpleated = 5*gray\ pleated + 2*gray\ nonpleated$ (eq5)

Using (eq3) and (eq4) in (eq5), we have:

$333 = 2*225 + 3*gray\ pleated$

$gray\ pleated = 117/3 = 39$

From (eq1), we have:

$blue\ pleated = 5*39 = 195$

From (eq3), we have:

$blue\ nonpleated = 333 - 195 = 138$

3 0

3 years ago

Graph the line y-5=3/2(x+1)

Vitek1552 [10]

slope: 3/2

y-intercept: 13/2

7 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

A forest ranger can see for a distance of 12 miles from a firetower. Formulas Show calculator Select the best answer How many sq

BabaBlast [244]

That would be the area of a circle of radius 12 miles

= pi r^2 = 452.4 square miles to nearest tenth.

6 0

3 years ago