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Georgia [21]
3 years ago
5

Compose the shaded fraction into larger fractional units. Express the equivalent fractions in a number sentence using division.

The first one has been done for you.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0

The solution is in the attachment

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(2.01) solve -2(2x + 5) - 3 = -3(x - 1)
steposvetlana [31]
<span>solve -2(2x + 5) - 3 = -3(x - 1)

-4x - 10 -3  = -3x + 3
-4x - 13 = -3x + 3

Add 3x to both sides
-4x - 13 +3x = -3x +3

Simplify
-x - 13 = 3
Add 13 to both sides
-x - 13 + 13 = 3 + 13

Simplify 
-x = 16

multiply both sides by (-1) 
x = -16</span>
6 0
4 years ago
Read 2 more answers
A man has 32 coins in his pocket, all of which are dimes and quarters. If the total value of his change is 545 cents, how many d
inn [45]

A dime is worth 10 cents and a quarter is worth 25 cents.

Let D be the number of dimes and Q be the number of quarters.

Since the total amount of coins in the pocket is 32, then:

D+Q=32

On the other hand, the total value of D dimes is 10D, while the total value of Q dimes is 25Q. Then, the total value of D dimes and Q cuarters is 10D+25Q, which must be equal to 545. Then:

10D+25Q=545

Notice that we have found a 2x2 system of equations:

\begin{gathered} D+Q=32 \\ 10D+25Q=545 \end{gathered}

Solve the system using the substitution method. To do so, isolate D from the first equation and replace the expression for D into the second equation to obtain a single equation in terms of Q:

\begin{gathered} D+Q=32 \\ \Rightarrow D=32-Q \\  \\ 10D+25Q=545 \\ \Rightarrow10(32-Q)+25Q=545 \\ \Rightarrow320-10Q+25Q=545 \\ \Rightarrow25Q-10Q=545-320 \\ \Rightarrow15Q=225 \\ \Rightarrow Q=\frac{225}{15} \\  \\ \therefore Q=15 \end{gathered}

Replace back Q=15 into the expression for D to find the amount of dimes:

\begin{gathered} D=32-Q \\ =32-15 \\ =17 \end{gathered}

Therefore, the amount of dimes that the man has is 17.

7 0
1 year ago
Attached is the questions i need help with.
bekas [8.4K]

Answer:


Step-by-step explanation:

Reasons:

3. The measures of supplementary angles add up to 180* (2)

5. Definition of Congruence (4)

6. Substitution Postulate (3,5)


EDIT: Your statement and proof column is cut off, so I can't see the other statements to completely fill in the reasons column.

5 0
3 years ago
Need Help
klio [65]

The smallest amount of material needed is 54 square centimeters

<h3>How to determine the amount of material needed?</h3>

The given parameters are:

Volume = 36 cubic centimeters

Represent length with x, width with y and height with z.

So, we have

x = 3y

The volume is calculated as:

V = xyz

This gives

V = 3y²z

Substitute 36 for V

3y²z = 36

Divide by 3

y²z = 12

Make z the subject

z = 12/y²

The surface area is:

S = 2(xy + xz + yz)

This gives

S = 2(3y² + 3yz + yz)

Evaluate the like terms

S = 2(3y² + 4yz)

Expand

S = 6y² + 8yz

Substitute z = 12/y²

S = 6y² + 8y * 12/y²

This gives

S = 6y² + 96/y

Differentiate

S' = 12y -  96/y²

Set to 0

12y -  96/y² = 0

Multiply through by y²

12y³ - 96 = 0

Add 96 to both sides

12y³ = 96

Divide by 12

y³ = 8

Take the cube root of both sides

y = 2

Recall that:

x = 3y and z = 12/y²

This gives

x = 3 * 2 = 6

z = 12/2² = 3

Recall that:

S = 2(xy + xz + yz)

So, we have:

S = 2(6 * 2 + 3 * 3 + 2 * 3)

Evaluate

S = 54

Hence, the smallest amount of material needed is 54 square centimeters

Read more about surface areas at:

brainly.com/question/76387

#SPJ1

8 0
3 years ago
Which of the sets of equations represent the two lines graphed?
shutvik [7]

Answer:

y = x + 2

y =-x - 4

Step-by-step explanation:

Find the slope and y-intercept of each lines to write the equation in slope intercept form: y = mx + b where m is the slope and b is the y-intercept

3 0
4 years ago
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