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Mrrafil [7]
3 years ago
8

The paint in a certain container is sufficient to paint an area equal to 9.375 m^2. How many bricks of dimensions 22.5 cm × 10 c

m × 7.5 cm can be painted out of this container?
Mathematics
1 answer:
Minchanka [31]3 years ago
8 0
Let l = 22.5 cm, b = 10 cm and h = 7.5 cm
Surface area of each brick
= 2(lb + bh + lh)
= 2(22.5 × 10 + 10 ×7.5 + 7.5 × 22.5 cm²
= 2 (225 + 75 + 168.75) cm²
= 2(468.75) cm² = 937.5 cm²

Area that can be painted using the paint of container = 9.375 m² = 9.375 × 100 × 100 cm²

Number of bricks that can be painted
=   \frac{Total \: area \: that \: can \: be \: painted}{ Surface \: area \: of \: each \: brick }
=  \frac{9.375 \times 100 \times 100 \: cm {}^{2} }{937.5 \: cm {}^{2} }  = 100

Hence, 100 bricks can be painted out of the paint given in the container.
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Simplify the expression<br> 70.7-5.76
Romashka-Z-Leto [24]

Answer:

64.94

Explanation

You arrange the numbers in such a way, to be in line with their decimal points like this:

70.7

-5.76

Then you subtract. Notice that on top of the 6 is nothing which is equal to 0

3 0
2 years ago
Simplify the expressions.1 a. –2 t + 5 t – 2 – t
masha68 [24]

Answer:

1 a.) 2t – 2

1 b.) –9z + 4

2 a.) –2v + 3

2 b.) –13k – 9

3 a.) 7w  − 2

3 b.) 10s

4 a.) 5

4 b.) –3p + 11

5 a.) –29x + 9

b.) 15v – 60x – 2

a.) 25n + 2

b.) –15n

a.) –71x + 4

b.) –15b

Step-by-step explanation:

  • <em>NOTE: I am kind of confused about the way this question is formatted, so I tried to answer everything I could decipher.</em>

1 a.) –2t + 5t – 2 – t →  2t – 2

1 b.) –5z + 4 – 4z →  –9z + 4

2 a.) 8v + 3 – 10v →  –2v + 3

2 b.) –6 – 6k – 3 – 7k →  –13k – 9

3 a.) –6 – 3w + 4 + 10w →  7w  − 2

3 b.) 9s + s →  10s

4 a.) 6 + 8b – 1 – 8b →  5

4 b.) 1p + 6 + 5 – 4p →  –3p + 11

5 a.) 4x – 3x + 9 – 6x 5 →  –29x + 9

b.) 9v + 6v – 2 – 10x 6 →  15v – 60x – 2

a.) n + 2 – (–4)n 6 →  25n + 2

b.) 6n – 3n 7 →  –15n

a.) –4x – 4x + 4 – 9x 7 →  –71x + 4

b.) –9b + (–6)b →  –15b

7 0
3 years ago
A jury pool consists of 50 potential jurors and how many ways can a jury of 12 be selected
bija089 [108]

Solution:

we are given that

A jury pool consists of 50 potential jurors.

Wee have been asked to find the number of ways can a jury of 12 be selected.

As we know from the concept of combination that r person can be selected out of n in ncr ways. where

n_C_r=\frac{n!}{r!(n-r)!}

Now substitute the values we get

{50}_C_{12}=\frac{50!}{12!(50-12)!}\\&#10;\\&#10;{50}_C_{12}=\frac{50!}{12!38!}\\&#10;\\&#10;{50}_C_{12}=121399651100\\

Hence the required number of ways is 121399651100

5 0
3 years ago
An FBI survey shows that about 30% (i.e., 0.3) of all property crimes go solved. Suppose that in New York City 15 such crimes ar
konstantin123 [22]

Complete question :

An FBI survey shows that about 30% (i.e., 0.3) of all property crimes go solved. Suppose that in New York City 15 such crimes are committed and they are each deemed independent of each other.

a. What is the probability that exactly 3 of these 15 crimes will be solved? b. What is the probability that at most 3 of these 15 crimes will be solved? c. What is the probability that more than 11 of these 15 crimes will be solved?

Answer:

0.17

0.29686

0.000092

Step-by-step explanation:

Given that :

Probability of success (p) = 0.3

Number of cases (n) = 15

1 - p = 1 - 0.3 = 0.7

Usung binomial distribution formula :

a. What is the probability that exactly 3 of these 15 crimes will be solved?

P(x = 3)

Recall:

P(x = x) = nCx * p^x * (1 - p)^(n-x)

P(x = 3) = 15C3 * 0.3^3 * 0.7^12

P(x = 3) = 455 *

P(x = 3) = 0.17

B.) What is the probability that at most 3 of these 15 crimes will be solved?

P( X ≤ 3) = P(x = 0) + p(x = 1) + p(x = 2) + p(x = 3)

To save computation time, we can using the binomial probability calculator :

P( X ≤ 3) : 0.00474 + 0.03052 + 0.09156 + 0.17004 = 0.29686

c. What is the probability that more than 11 of these 15 crimes will be solved?

P( X > 11) = P(x = 12) + p(x = 13) + p(x = 14) + p(x = 15)

P( X > 11) = 0.000092

7 0
3 years ago
M &lt; TYV=64°<br><br> What is m<br> A.116°<br> B.90°<br> C.26°<br> D.64°
solmaris [256]
My answer to this question C
4 0
3 years ago
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