The paint in a certain container is sufficient to paint an area equal to 9.375 m^2. How many bricks of dimensions 22.5 cm × 10 c
1 answer:
Let l = 22.5 cm, b = 10 cm and h = 7.5 cm
Surface area of each brick
= 2(lb + bh + lh)
= 2(22.5 × 10 + 10 ×7.5 + 7.5 × 22.5 cm²
= 2 (225 + 75 + 168.75) cm²
= 2(468.75) cm² = 937.5 cm²
Area that can be painted using the paint of container = 9.375 m² = 9.375 × 100 × 100 cm²
Number of bricks that can be painted
Hence, 100 bricks can be painted out of the paint given in the container.
Surface area of each brick
= 2(lb + bh + lh)
= 2(22.5 × 10 + 10 ×7.5 + 7.5 × 22.5 cm²
= 2 (225 + 75 + 168.75) cm²
= 2(468.75) cm² = 937.5 cm²
Area that can be painted using the paint of container = 9.375 m² = 9.375 × 100 × 100 cm²
Number of bricks that can be painted
Hence, 100 bricks can be painted out of the paint given in the container.
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Check the picture below.
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well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180, meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).
alrighty, by the inscribed angle theorem, ∡A is half of ∡O.
let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.
now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.
Answer:
Step-by-step explanation:
Given
Required
Solve
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
<em>The numbers in parentheses are carried from previous sum</em>
Start from the right
Write 0, carry 1
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
0
Write 0 carry 1
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
0 0
Write 0 carry 1
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
0 0 0
Write 0 carry 1
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
0 0 0 0
Write 0 carry 1
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
0 0 0 0 0
Write 0 carry 1
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
0 0 0 0 0 0
Write 0 carry 1
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
0 0 0 0 0 0 0
Write 6
2 4 5 6 7 3 8 9
+ 3 5 4 3 2 6 1 1
----------------------------
6 0 0 0 0 0 0 0
Hence: