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garik1379 [7]
3 years ago
13

When I add my second number to twice my first number, the total is 10. When I add twice my second number to my first number, the

total is 11?
Mathematics
1 answer:
Murljashka [212]3 years ago
4 0
<u>Define x and y:</u>
Let the first number be x and the second number be y.

<u>Setup the equations:</u>
y + 2x = 10 ----------- (1)
2y + x = 11  ----------- (2)

<u>Solve x;</u>

From (1):
y + 2x = 10
y = 10 - 2x  ----------- Sub into (2)

2(10 - 2x) + x = 11
20 - 4x + x = 11
20 - 3x = 11
3x = 20 - 11
3x = 9
x = 3  ----------- Sub into (1)

y + 2(3) = 10 
y = 10 - 6
y = 4

<u>Find the numbers:</u>
First number = x = 3
Second number = y = 4

Answer: The two numbers are 3 and 4.
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3 years ago
Solve the equation using the order of operations.<br><br> 5+{2×[(5−1)+6]}÷4
creativ13 [48]

Answer:

The order of operations is PEMDAS

First step is to do everything is parenthesis or brackets

5+{2*[(5-1)+6]}/4

{2*[(5-1)+6]}

First you would go 5-1=4, because that is the first equation that is in parenthesis by itself.

{2*[4+6]}

Next you would go 4+6=10, because that is your next smallest bracket

{2*10}

Last you would go 2*10=20

Your equation now looks like this

5+{20}/4

In PEMDAS your next step is exponents, but we don't have any so we go on to the next one which is multiply/division

5+5

You would go 20/4=5

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Your final answer would be 10

Hope this helps ;)

Step-by-step explanation:

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