A pattern of being late for or for appointments is usually
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When it comes to laplace equations, there are transformation equations to follow. Generally, when you want to transform a laplace equation, you change the equation from f(t) to F(s). If you do the reverse, it is called the reverse laplace equation.
Based on the given, the useful transformation equation is shown in the attached picture.
When the term is s^2, that must mean that the equation is 1!/s^(1+1) to yield 1/s^2. This means that n=1. Taking the reciprocal s^2 must be equal to 1/t. Thus, for the first term, -11s^2 is equal to -11/t. For the second term, n must be equal to 6 so that 6!/s^(6+1) would yield 720/s^7. Thus, 720s^7 is equal to 1/t^6.
Hence, the transformed equation is -11/t - 1/t^6
Based on the given, the useful transformation equation is shown in the attached picture.
When the term is s^2, that must mean that the equation is 1!/s^(1+1) to yield 1/s^2. This means that n=1. Taking the reciprocal s^2 must be equal to 1/t. Thus, for the first term, -11s^2 is equal to -11/t. For the second term, n must be equal to 6 so that 6!/s^(6+1) would yield 720/s^7. Thus, 720s^7 is equal to 1/t^6.
Hence, the transformed equation is -11/t - 1/t^6
Answer:
Fourth term: =
=
Fifth term: =
= 1
Sixth term:
Step-by-step explanation:
The geometric progression is:
The first term, a, is 9
To find the common ratio, r, all we have to do is divide a term by its preceding term.
Let us divide the second term by the first:
That is the common ratio.
Geometric progression is given generally as:
where a = first term
r = common ratio
= nth term
We need to find the 4th, 5th and 6th terms.
Fourth term: =
=
Fifth term: =
= 1
Sixth term: