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Genrish500 [490]
3 years ago
10

What set describes the zeroes of the function f(x )= 6πsin(4x) shown in the graph?

Mathematics
1 answer:
gogolik [260]3 years ago
8 0

Answer:

"[x|x=\frac{k}{4}\pi] for every integer k"


Step-by-step explanation:

The function has zeroes at the x-intercepts in the graph.

If you look at the graph from 0 to \pi, you will see that the graph cuts the x-axis at 4 points.

They are at half of \frac{\pi}{2}, which is \frac{\pi}{4}, at \frac{\pi}{2}, at half point between \frac{\pi}{2} and \pi, which is at \frac{3\pi}{4}, and at \pi.


They are basically all multiples of \frac{\pi}{4}.

Looking at the answer choices, the third choice is correct.

Plugging in k=1, k=2, k=3, and k=4 into the equation, we see that the zeroes are exactly what we saw. Also, the negative side of the function holds true as well.

Third answer choice is right.

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At 7:00 p.m., there are 1,000 home-team fans and 700 away-team fans at a football game. After 7:00 p.m, 15 home team fans arrive
OleMash [197]

Answer:

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=109:67

Step-by-step explanation:

Initially , total home team fans =1000

and away team fans = 700.

7:00 pm to 8:00 pm = 1 hour = 60 minutes

Given that

Every 10 minutes the number of arrival home team fans is 15.

Then in 1 minutes the number of arrival home team fans is \frac{15}{10}

and in 60 minutes the number of arrival home team fans is \frac{15 \times 60}{10}  

                                                                                                 =90

Therefore total home team fans = (90+1000)=1090

Given that

Every 10 minutes 5 fans leave of away team  leave.

then in  1 minutes \frac{5}{10}  fans leave of away team  leave.

and In 60 minutes \frac{5\times 60}{10} =30  fans leave of away team  leave.

Since 30 away team fans leave.

Total away team fans = (700-30)=670

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=1090:670

=109:67

4 0
3 years ago
Correct answer gets 25 points! Help please!
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