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mafiozo [28]
3 years ago
15

8 plus 3 cubed over 12-7

Mathematics
1 answer:
Finger [1]3 years ago
4 0

Answer:

7

Step-by-step explanation:

8+3³/12-7

8+27/5

35/5

7

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Bryan is setting charis in rows for graduation ceremony he has 50 black chars,and 60 white charis each row will have the same nu
konstantin123 [22]
Assuming that no row can have a combination of black and white chairs, there will be 11 rows, each consisting of 10 chairs. 5 of these rows will have black chairs, and 6 of these rows will have white chairs. I arrived at this by finding the GCF (or greatest common multiple) of 50 and 60, which is 10. That number represents the maximum number of chairs per row. Then, I added 50 and 60, to get 110, and divided that by the number of chairs per row, 10, to arrive at there being 11 rows. 50/110 chairs are black, meaning 5 rows are black, and 60/110 chairs are white, meaning 6 rows are white. Hope this helps! <em>~ArchimedesEleven</em>
5 0
3 years ago
Read 2 more answers
What is the volume of the cylinder?
Vesna [10]
The answer is a.
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3 years ago
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Work out an expression for the nth term for this sequence:<br><br> 23,35,47,49
notsponge [240]
<h3>Answer:</h3>

a_n = 23 +12(n -1)

<h3>Explanation:</h3>

The nth term of an arithmetic sequence is explicitly defined as a_n = a_1 +d(n -1) where a_1 is the first term of the sequence and d is the the common difference.

From the given first five terms of the sequence we can see that the first term is 23 so a_1 = 23.

The common difference, d, can be calculated by a_n - a_{n -1} so we'll find the common difference of the given sequence by letting n = 2

d = a_2 - a_{2 -1} \\d = a_2 -a_{1} \\d = 35 -23 \\ d = 12.

Now let's plug everything we know.

a_1 = 23

d = 12

a_n = 23 + 12(n -1)

7 0
2 years ago
23 2/5−11 4/5 Enter your answer as a mixed number in simplest form.
oksian1 [2.3K]

Answer:

11 3/5

Step-by-step explanation:

23 2/5-11 4/5

22 7/5-11 4/5

11 3/5

7 0
3 years ago
Non proportional or proportional
Elan Coil [88]
Non proportional it should be
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3 years ago
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