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scoundrel [369]
3 years ago
9

John is building a fence for the animals on his farm. The perimeter of the rectangle should be less than 100 meters. The length

of the rectangle is 4 meters more than the width. Which inequality expresses all of the possible widths, in meters, of the rectangle?
Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

Step-by-step explanation:

Let the width w = x

Length l = 4x

Perimeter of rectangle= 2(l + w)<100

2(x + 4x) < 100

2(5x) < 100

10x < 100

x < 100/10

x < 10

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the sum of three numbers is 79. The second number is 5 times the first, while the third is 16 more than the first. Find the Numb
faust18 [17]
Let the 1st number be x; 2nd number be y; 3rd number be z.

x + y + z = 79

x = number we are looking for.
y = x * 5 ==> 5 times the first
z = x + 16 ==> 16 more than the first

Therefor,

x + (x * 5) + (x+16) = 79

1st step, multiply the 2nd number: x * 5 = 5x

x + 5x + x + 16 = 79

Add all like numbers:

7x + 16 = 79

To get x, transfer 16 to the other side and change its sign from positive to negative.

7x = 79 - 16
7x = 63

To get x, divide both sides by 7

7x/7 = 63/7
x = 9

To check. Substitute x by 9.

x + (x * 5) + (x+16) = 79

9 + (9 * 5) + (9 + 16) = 79
9 + 45 + 25 = 79
79 = 79 equal. value of x is correct.

4 0
3 years ago
Read 2 more answers
Bject?
Yakvenalex [24]

Answer:

The entire volume would be 60m, but if it's talking only about the little rectangle on top then the answer is 6m.

Step-by-step explanation:

The length of the smaller object is 1m, the height is 2m, and the width is 3m (as seen to the right side near the bigger block).

Multiply all those numbers together (1×2=2, 2×3=6 or just simply 1×2×3=6)

5 0
2 years ago
Read 2 more answers
Can someone help me with this I’m very confused
shepuryov [24]

Answer:

is this a question meant to evaluate you, such as a test, exam, quiz, or assessment?

5 0
2 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
Estimate 58,088-39,625 by first rounding each number to the nearest thousand.
Tpy6a [65]

Answer:

Here is the answer, I took it as simple I could.

7 0
2 years ago
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