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3 years ago

5(a + 2b) Please help me on this problem

Mathematics

2 answers:

anastassius [24]3 years ago

6 0

Answer:

5a+10b

Step-by-step explanation:

5a+5(2b)

just olya [345]3 years ago

3 0

If you are looking to get it into standard form, you distribute the 5 to get 5a+10b

You might be interested in

The 180 falls between which two whole numbers? A) 11 and 12 B) 12 and 13 C) 13 and 14 D) 14 and 15

Umnica [9.8K]

Answer:

C) 13 and 14

Step-by-step explanation:

To find the answer, we need to check for all the options.

A) 11 and 12 = 11 *12 = 132

B) 12 and 13 = 12 *13 = 156

C) 13 and 14 = 13*14 = 182

D) 14 and 15 = 14*15 = 210

In which, C) is true.

It is 182 which falls in 180's

Therefore, answer is C) 13 and 14

Hope this will helpful.

Thank you.

7 0

3 years ago

Read 2 more answers

How do you solve this ?

pickupchik [31]

If t=-3 (hopefully it does) then it's 6+-12/10. This is -6/10=-3/5

3 0

3 years ago

Round 492.3069 to the nearest thousandth

Llana [10]

The answer is 492.307
The number after the thousandths is 9 - greater than 5 - so we round 6 up to 7.

4 0

3 years ago

A pro baseball team is having a promotion in which every 10th fan that enters the stadium gets a free hat and every 12th person

mixas84 [53]

Multiples of 10 = 10, 20, 30, 40, 50, 60
This means the 10th, 20th, 30th, 40th, 50th, 60th, ... fan will get a free hat.
Multiples of 12 = 12, 24, 36, 48, 60
This means the 12th, 24th, 36th, 48th, 60th, ... fan will get a free shirt.
So the 60th fan will receive both a hat and a shirt.
Meaning 60 fans will come to the stadium before a fan receives both a hat and a shirt.

3 0

3 years ago

An elementary school is offering 3 language classes: one in Spanish, one in French,and one in German. The classes are open to an

Alona [7]

Answer:

A. 0.5

B. 0.32

C. 0.75

Step-by-step explanation:

There are

28 students in the Spanish class,
26 in the French class,
16 in the German class,
12 students that are in both Spanish and French,
4 that are in both Spanish and German,
6 that are in both French and German,
2 students taking all 3 classes.

So,

2 students taking all 3 classes,
6 - 2 = 4 students are in French and German, bu are not in Spanish,
4 - 2 = 2 students are in Spanish and German, but are not in French,
12 - 2 = 10 students are in Spanish and French but are not in German,
16 - 2 - 4 - 2 = 8 students are only in German,
26 - 2 - 4 - 10 = 10 students are only in French,
28 - 2 - 2 - 10 = 14 students are only in Spanish.

In total, there are

2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.

The classes are open to any of the 100 students in the school, so

100 - 50 = 50 students are not in any of the languages classes.

A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

$\dfrac{50}{100} =0.5$

B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is

$\dfrac{8+10+14}{100}=0.32$

C. If 2 students are chosen randomly, the probability that both are not taking any language classes is

$0.5\cdot 0.5=0.25$

So, the probability that at least 1 is taking a language class is

$1-0.25=0.75$

3 0

3 years ago