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s2008m [1.1K]
3 years ago
11

5(a + 2b) Please help me on this problem

Mathematics
2 answers:
anastassius [24]3 years ago
6 0

Answer:

5a+10b

Step-by-step explanation:

5a+5(2b)

just olya [345]3 years ago
3 0
If you are looking to get it into standard form, you distribute the 5 to get 5a+10b
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the temperature at 6:00AM was 0.8F. BY. 3:00pm the temperature had increased to 2.4 F find the differnce between the two tempera
Tom [10]
0.8+2.4= 10.4F it increased 10.4f from 6am to 3am
4 0
3 years ago
Speeding: On a stretch of Interstate-89, car speed is a normally distributed variable with a mean of 69.1 mph and a standard dev
Alborosie

Answer: 11.9%

Step-by-step explanation:

Given :  On a stretch of Interstate-89, car speed is a normally distributed variable with \mu=69.1 mph and \sigma=3.3 mph.

Let x be a random variable that represents the car speed.

Since , z=\dfrac{x-\mu}{\sigma}

z-score corresponds x = 73 , z=\dfrac{73-69.1}{3.3}\approx1.18

Required probability :

\text{P-value }: P(x>73)=P(z>1.18)\\\\=1-P(z

[using z-value table.]

Hence, the approximate percentage of cars are traveling faster than you = 11.9%

8 0
3 years ago
Name the Property of Equality that justifies the statement: If m<A + M<B = M<C. Then, M<A = M<C - M<B
adoni [48]
The subtracton property of equality allows you to subtract the same amount from both sides of an equation without changing the truth of the equation.
5 0
2 years ago
Emmett gathered some data to compare the monthly cost of renting a one-bedroom apartment in Dallas and Austin. The data collecte
Goryan [66]

Answer:

The correct options are;

a) The city's data has the higher median monthly apartment cost of the two cities by $155

b) The city's data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data

Step-by-step explanation:

The given data for the cost of renting a one-bedroom apartment in Dallas is presented as follows;

$994, $1,322, $1,075, $1,189, $1,172, $1,465, $1,215, $930, $1,090, $1,288

Which can be arranged in increasing order and analyzed to find the interquartile range, mean and standard deviation using Microsoft Excel as follows;

$930, $994, $1,075, $1,090, $1,172, $1,189, $1,215, $1,288, $1,322, and $ 1,465

The first quartile, Q₁ = $1,054.75

The third quartile, Q₃ = $1,296.5

The interquartile range = Q₃ - Q₁ = $241.75

The median = $1,180.5

The average monthly cost = $1,174

The standard deviation of the sample = $159.9597

The given data for the cost of renting a one-bedroom apartment in Austin is presented in increasing order using Microsoft Excel as follows;

$900, $950, $1,100, $1,250, $1,296, $1,375, $1,389, $1,400, $1,450, $1,495

The interquartile range, mean and standard deviation are found using Microsoft Excel as follows;

The first quartile, Q₁ = $1,062.5

The third quartile, Q₃ = $1,412.5

The interquartile range = Q₃ - Q₁ = $1,412.5 - $1,062.5 = $350

The median = $1,335.5

The average monthly cost = $1,260.5

The standard deviation of the sample = $209.0945

The difference in the median cost of the two cities is $1,335.5 - $1,180.5 = $155

Therefore, the Austin's city data has the higher median monthly apartment cost of the two cities by $155

b) The difference in the sample standard deviation of the two cities is $209.0945 - $159.9597 = $49.13476

Therefore, the Austin city data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data.

7 0
3 years ago
Read 2 more answers
B) The elephant
Misha Larkins [42]

Answer:

what!?!!!?!.!?!!!?!!.

3 0
2 years ago
Read 2 more answers
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