Question

If 1.0 M HIM HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2H2 (gg)?

Answer 1

The given question is incomplete. The complete question is

If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2 (g). Given the equilibrium constant is 62.

Answer: The equilibrium concentration of $H_2$ is 0.498 M

Explanation:

Initial concentration of $HI$ = 1.0 M

The given balanced equilibrium reaction is,

                         $2HI(g)\rightarrow H_2(g)+I_2(g)$

initial                  (1.0) M                  0              0

At eqm               (1.0-2x) M               (x) M      (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[H_2]\times [I_2]}{[HI]^2}$

Now put all the given values in this expression, we get :

$62=\frac{(x)^2}{1.0-2x}$

By solving we get :

$x=0.498M$

Thus the equilibrium concentration of $H_2$ is 0.498 M