the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
The answer is 60 degrees
If the picture was: http://tinypic.com/view.php?pic=1zq6o75&s=7#.W1FNsNVKiM8
I hope this helps!
Plz mark brainliest!
What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other
(a-2)^3+8 = a^3-8+8 = a^3
= a^3 = b^3 square root both side = a=b
<span>(b-2)^3+8 = b^3-8+8 = b^3
Thus it is 1:1.</span>
Answer:
- 5 < x
Step-by-step explanation:
To solve, we need to isolate the variable: x
5x - 7 < 8x + 8
Subtract 5x from both sides
5x - 5x -7 < 8x -5x + 8
- 7 < 3x + 8
Subtract 8 from both sides
- 7 -8 < 3x + 8 -8
-15< 3x
Divide both sides by 3
- 15/3< 3x/3
- 5 < x
Answer:
with wut XD
Step-by-step explanation:
