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Natasha2012 [34]
2 years ago
11

How is solving an equation with no solution similar to solving an equation that has an infinite number of solutions?

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
7 0
Solving a equation with no solution is similar to solving an equation that has an infinite number of solutions because both will keep on going no matter how many times you will get no solution and no matter how many times you would get an infinite number
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A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ 
E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ 
P(E^{c})= \frac{3}{12} \\  \\ 
P(E^{c})= \frac{1}{4}
7 0
3 years ago
Mary made 1/5 of a batch of cookies in 1/10th of an hour, how many batches of cookies can she make in one hour? This is unit rat
barxatty [35]

Answer:

1/5 ÷ 1/10 = 10/5

Step-by-step explanation:

7 0
3 years ago
A rectangular prism has a volume of 16 cm3 and a total surface area of 40 cm2. A similar prism has length 10 in., width 5 in., a
Kruka [31]
We know that
[volume of the similar prism]=10*5*5----> 250 in³
volume original prism=16 cm³
 1 in³---------> 16.3871 cm³
X----------> 16
x=16/16.3871------> x=0.9764 in³

[volume of the similar prism]=[scale factor]³*[volume original prism]
[scale factor]³=[volume of the similar prism]/[volume original prism]
[scale factor]³=[250]/[0.9764]------> 256.05
scale factor=∛256.05-------> 6.35

<span>the dimensions of the original prism are
1 in-----> 2.54 cm

</span>length 10 in/6.35-------> 1.57 in*2.54 cm/in-----> 4 cm
<span>width 5 in/6.35---------> 0.79 in*2.54 cm/in-----> 2 cm
</span><span>height 5 in/6.35--------> 0.79 in*2.54 cm/in----> 2 cm</span>
3 0
3 years ago
How do you simplify 2i&lt;6u ?
marusya05 [52]
In simplifying inequalities, there are a few things that you have to remember. Here are some:

<span>Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own.
But these things will change direction of the inequality:<span>Don't multiply or divide by a variable (unless you know it is always positive or always negative)

We simplify as follows:
2i/2<6u/2
i<3u</span></span>
5 0
2 years ago
Please help me thank you
andre [41]

Answer:

Its the last one

Step-by-step explanation:

5 0
3 years ago
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