PLZ HELP!!!!

Order these decimals greatest to least 0.2 ; -0.4 ; -4.5

Mice21 [21]

0.2,
-0.4,
-4.5
hope this helps

6 0

3 years ago

Select steps that could be used to solve the equation 1 + 3x = -x + 4.

Tema [17]

For this case we have the following equation:

$1 + 3x = -x + 4$

We must solve the equation by following the steps below:

We subtract 1 from both sides of the equation:

$3x = -x + 4-1$

On the right side of the equation we have that different signs are subtracted and the sign of the major is placed:

$3x = -x + 3$

We add x to both sides of the equation:

$3x + x = 3\\4x = 3$

We divide between 4 on both sides of the equation:

$x = \frac {3} {4}$

Thus, the correct option is option B

Answer:

$x = \frac {3} {4}$

Option B

6 0

4 years ago

Read 2 more answers

Help please The area of the figure is blank square units

zimovet [89]

Answer:

132 square units

Step-by-step explanation:

First, I would figure out the areas of the right triangles

Left triangle: 1/2(6x8) =24 units²

Right triangle: 1/2(8x3) = 12 units²

entire rectangle between triangles: 12x8 = 96 units²

add all areas together: 24+12+96 = 132 units²

3 0

3 years ago

Read 2 more answers

Answer if u can plz

postnew [5]

Answer:

180 Area

Step-by-step explanation:

15 times 12 = 180 which would be the area:

may i have Brainliest?

5 0

3 years ago

Read 2 more answers

For questions, 1-2, determine whether experiment is a binomial experiment. If it is, identify a success, specify the values of n

horrorfan [7]

Answer:

Part 1

X="number of U.S. households that own a dedicated game console"

Is a binomial experiment we an event defined with the associated probability and we have specific trials.

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=8, p=0.49)$

Y= "number of cards that are hearts."

Thats not a binomial experiment since the probability for each trial changes since we are doing the experiment without replacment

Part 2

a) $P(X=2)=(6C2)(0.39)^2 (1-0.39)^{6-2}=0.316$

b) $P(X \geq 5) = P(X=5)+P(X=6)$

$P(X=5)=(6C5)(0.39)^5 (1-0.39)^{6-5}=0.033$

$P(X=6)=(6C6)(0.39)^6 (1-0.39)^{6-6}=0.00352$

$P(X \geq 5) = P(X=5)+P(X=6)=0.033+0.00352=0.0365$

Part 3

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=6, p=0.34)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Part 4

$E(X)=np=4*0.69=2.76$

The variance $\sigma^2 = np(1-p) = 4*0.69*(1-0.69) =0.8556$

$\sigma=\sqrt{np(1-p)}=\sqrt{4*0.69(1-0.69)}=0.925$

Unusual outcomes would be considered values above or below 2 deviations from the mean for example 2.76-(2*0.925) =0.91 or 2.76+2(0.925)=4.61[/tex]. X=0 and X=4 would be considered as unusual values.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Part 1

X="number of U.S. households that own a dedicated game console"

Is a binomial experiment we an event defined with the associated probability and we have specific trials.

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=8, p=0.49)$

Y= "number of cards that are hearts."

Thats not a binomial experiment since the probability for each trial changes since we are doing the experiment without replacment

Part 2

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=6, p=0.39)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

a) $P(X=2)=(6C2)(0.39)^2 (1-0.39)^{6-2}=0.316$

b) $P(X \geq 5) = P(X=5)+P(X=6)$

$P(X=5)=(6C5)(0.39)^5 (1-0.39)^{6-5}=0.033$

$P(X=6)=(6C6)(0.39)^6 (1-0.39)^{6-6}=0.00352$

$P(X \geq 5) = P(X=5)+P(X=6)=0.033+0.00352=0.0365$

Part 3

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=6, p=0.34)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Part 4

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=4, p=0.69)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

The expected value is given by:

$E(X)=np=4*0.69=2.76$

The variance $\sigma^2 = np(1-p) = 4*0.69*(1-0.69) =0.8556$

$\sigma=\sqrt{np(1-p)}=\sqrt{4*0.69(1-0.69)}=0.925$

Unusual outcomes would be considered values above or below 2 deviations from the mean for example 2.76-(2*0.925) =0.91 or 2.76+2(0.925)=4.61[/tex]. X=0 and X=4 would be considered as unusual values.

6 0

4 years ago