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Sever21 [200]
3 years ago
7

HELP!! I DON'T KNOW WHAT TO DO

Mathematics
2 answers:
Tomtit [17]3 years ago
6 0
Yeah it would be 7 cups
Kay [80]3 years ago
3 0
3 1/4 cups for 13 servings...
(3 1/4) / 13 =
13/4 * 1/13 =
13/52 which reduces to 1/4 cup per serving

for 28 servings...
1/4 * 28 = 28/4 = 7 cups <== 28 servings requires 7 cups of flour
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The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer se
tankabanditka [31]

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

7 0
2 years ago
Can someone help me plz
Lady bird [3.3K]
-4.25 because that is the only number out of those options between -4 and -5
8 0
3 years ago
Read 2 more answers
20 and 23 lcm and gcf
liraira [26]

Answer:

GCF: 1

LCM: 460

4 0
2 years ago
Read 2 more answers
Name the property used to solve the problem. 7(4x+20)=28x+140 (7∗4x)+(7∗20) 28x+140
ANTONII [103]

Answer:

I think this is how u spell it

Step-by-step explanation:

Disturbtive

7 0
3 years ago
How many 5/8s are in 3?
stira [4]
I believe it to be 4 because 3=24/8

So 5/8 + 5/8 = 10/8 + 5/8 = 15/8 + 5/8 = 20/8 + 5/8 = 25/8, which is the closest number to 3
4 0
3 years ago
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