Question

Write a vector equation of the line that passes through point P(-4,11) and is parallel to a=[-3,8]. Then write parametric equations of the line.

Answer 1

Answer:

$\vec l = (-4, 11) + t\cdot (-3,8)$, $x = -4 - 3\cdot t$ and $y = 11 + 8\cdot t$

Step-by-step explanation:

The vector equation of the line is:

$\vec l = \vec P + t \cdot \vec A$

$\vec l = (-4, 11) + t\cdot (-3,8)$

The parametric equations of the line are:

$x = -4 - 3\cdot t$ and $y = 11 + 8\cdot t$