3 years ago

Nikki ran 56 yards ran 18 yards what is the difference in the distance they ran

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

5 0

The difference they ran is 38 yards

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Please help me!! Il give u brainliest(:

baherus [9]

Answer: f^-1(x)= 2-4x/3

This is because the power of f is -1

7 0

2 years ago

Simplify the following expression.<br><br> ‐3 + 7(a – 3b – 1) – 4(10 – a + 2b)

mihalych1998 [28]

Answer:

11a − 29b − 50

Step-by-step explanation:

Subtract 7 from − 3

7a − 21b − 10 − 40 + 4a − 8b

Add 7a and 4a

11a - 21b - 10 - 40 - 8b

Subtract 8b from -21b

11a - 29b - 10 - 40

Subtract 40 from -10

11a - 29b - 50

7 0

1 year ago

Read 2 more answers

How many times do you need to multiply 271.96 by ten to get 2719.6

ivann1987 [24]

Every 10 you multipy by moves the decimla place to the right by 1 place
so it moves 1 place so therefor you need to multipy it by 10 ONE time
answer is 1 times

7 0

3 years ago

Which of the following is the solution to 4/5 = 20/(x-5)?

Alexxandr [17]

Answer:

x=30

Step-by-step explanation:

$\frac{4}{5}=\frac{20}{x-5} \\\\4(x-5)=20*5\\\\4x-20=20(5)\\\\4x=20(5)+20(1)\\\\4x=20(5+1)\\\\4x=20(6)\\\\x=\frac{20(6)}{4} \\\\x=5*6\\\\x=30$

8 0

3 years ago

Read 2 more answers

Standard equation of circle with center of (6,8) that passes through point (-1,4)

dezoksy [38]

Answer:

The result should be:

$(x-6)^2+(y-8)^2=\sqrt{65}$

Step-by-step explanation:

-The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$ where the center is $(h,k)$ , the point $(x,y)$ and the radius known as $r$ .

-Use the center (6,8) and the point (-1,4) for this equation:

$(-1-6)^2+(4-8)^2=r^2$

-Then, you solve for the radius and get the equation:

$(-1-6)^2+(4-8)^2=r^2$

$(-7)^2+(-4)^2 =r^2$

$49 + 16 = r^2$

$65 = r^2$

$\sqrt{65} =\sqrt{r^2}$

$\sqrt{65} = r$

-Result:

$(x-6)^2+(y-8)^2=\sqrt{65}$

5 0

2 years ago