Ask question

Ask question

All categories

3 years ago

13

karen sells clothes. after studing her constraints, she knows that she will make $10 profit on each jacket, j, she sells and $6

profit on each shirt, s, she sells. which equation or inequaltiy should she use to show her maximum profit , P?

2 answers:

romanna [79]3 years ago

8 0

The answer would have to be 10x- 6x= p

Tcecarenko [31]3 years ago

3 0

10x-6x=P

Hope this helps!

You might be interested in

Galina-37 [17]

Answer:

59.7

Step-by-step explanation:

you divide 39.80 by 10

then times it with 15 and get your answer

7 0

3 years ago

Combine equations<br> -5x - 9y = -2<br> 5x - 9y = 3

Sever21 [200]

The answer is -18y = 1 because the 5s cancel out

4 0

3 years ago

If f(x) = x2, and<br> g(x) = x – 1, then<br> f(g(x)) = [? ]x2+[?]+ [?]

Basile [38]

Answer:

f(g(x)) = x² - 2x + 1

Step-by-step explanation:

To find f(g(x)), substitute x = g(x) into f(x) , that is

f(g(x))

= f(x - 1)

= (x - 1)² ← expand using FOIL

= x² - 2x + 1

5 0

3 years ago

Log5(x-1)+log5(x+3)-1=0

jonny [76]

Answer:

there are no real solutions

Step-by-step explanation:

$\log_5(x-1)+\log_5(x+3)-1=0\\\\\log_5(x-1)+\log_5(x+3)=1$

there is a rule that says

$\log_b(a)+\log_b(c)=\log_b(ac)$

so we have

$\log_5(x-1)+\log_5(x+3)=\log_5((x-1)(x+3))=1$

and we have the definition

$\log_a(b)=c\\\\a^{c} =b$

so we have

$5^{1} = (x-1)(x+3)\\\\5=x^{2} -1x+3x-3\\\\5=x^{2} +2x-3\\\\0=x^{2} +2x-3-5\\\\0=x^{2} +2x-8\\\\$

and using the quadratic formula we get that

there are no real solutions

3 0

4 years ago

Read 2 more answers

Why did the hen run away

Llana [10]

To across the road.......

5 0

4 years ago

Read 2 more answers