Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)
Multiply equation (1) by 2:
22x + 30y + 46 = 0
Multiply equation (2) by 15:
105x - 30y - 300 = 0
Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]
Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3
Therefore, x = 2 and y = -3.
Answer:
188
Step-by-step explanation:
take notes
I got y^2/2
My Solution:
√9^2/18 · y^2
= 1/2 y^2
Multiply Fractions: a · (b/c) = (a · b)/c
1·y^2/2
=y^2/2
Hope I helped,
Faith xx
Answer: ( x - 1 ) ( x + 4 ) = 0.
Step-by-step explanation:
Let's see 1. To make this equal to zero you write x - 1 where you substitute 1 in x.
Again let's see -4. To make it equal to zero, you write x + 4 where you substitute -4 in x.
So, this results in ( x - 1 ) ( x + 4 ) = 0
