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3 years ago

WILL GIVE BRAINLIEST!!!!

Mathematics

1 answer:

aniked [119]3 years ago

4 0

It’s 57.66. 50.54+3.8+3.32

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This is 4/8 questions im giving brainliest for pls help me :D

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I don't really know but I think that it's B

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3 years ago

Me ayudan alguien/ can someone help me!!!

Tresset [83]

Answer:

divide perimeter by 3

Step-by-step explanation:

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Identify the lateral area and surface area of a regular triangular pyramid with base edge length 14 cm and slant height 15 cm.

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17 in long 1.3 ft wide and 8in high what is the volume

OverLord2011 [107]

Answer:

135.2

Step-by-step explanation:

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3 years ago

Read 2 more answers

In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en

jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

Step(i):-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in Swahili language

n(S) = 125

The probability that the fluent in Swahili language

$P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333$

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in English language

$P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9$

n(E∩S) = 95

The probability that the fluent in English and Swahili

$P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633$

Step(ii):-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

= 0.833+0.9-0.633

= 1.1

Final answer:-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0

3 years ago