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11Alexandr11 [23.1K]
3 years ago
9

The formula A=P(1+r)t is used to show the total amount owed for a loan with a simple annual interest rate.

Mathematics
2 answers:
Aleks04 [339]3 years ago
7 0

Answer:  r=(\frac{A}{P})^{\frac{1}{t}}-1


Step-by-step explanation

Compound interest is the addition of interest to the principal sum of a deposit or a loan.

Let P = principal amount which was taken as a loan then the accumulated amount A is given by

A=P(1+r)^t.......(1)

where, r is the rate of simple annual interest in decimal.

t is the time applied for interest.

For solving r divide both sides of equation by P in (1),we get

\frac{A}{P}=(1+r)^t\\\Rightarrow(\frac{A}{P})^{\frac{1}{t}}=1+r\\\Rightarrow\ r=(\frac{A}{P})^{\frac{1}{t}}-1.

vodka [1.7K]3 years ago
5 0
We are asked to express r in terms of A, P, and t.

We first divide both sides of the equation by t, which gives us

                                         
                     \displaystyle{ \frac{A}{t}=P(1+r), 


then, dividing both sides by P, we have

                     \displaystyle{ \frac{A}{Pt}=1+r.

Swap the sides:

                    \displaystyle{ 1+r= \frac{A}{Pt} 
      
Finally subtracting 1 from both sides gives us

                     \displaystyle{ r=\frac{A}{Pt}-1.


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URGENT!!! 50 POINTS!!! URGENT!!!!!!! Consider the polynomial functions P (x) and Q (x)​ , where neither polynomial is a constant
Nutka1998 [239]

Answer:

Always

Always

Sometimes

Never

Step-by-step explanation:

P(X) + Q(X)

Sum of two polynomials is always a polynomial.

For example, Let P(x) = 3x² and Q(x) = 5x

$ \implies P(x) + Q(x) = 3x² + 5x

This is again a polynomial.

In other words, we can say that Polynomial is closed under addition.

P(x) . Q(x)

Product of two polynomials is again a polynomial.

Let P(x) = 2x and Q(x) = a constant function, 5

Then the product = 10x, is again a polynomial.

Multiplication of two polynomials is closed.

P(x) / Q(x)

This need not always be a polynomial. When Q(x) = a constant function zero, i.e., Q(x) = 0, then the function is not defined.

But let's say P(x) = 5x² and Q(x) = x.

$ \frac{P(x)}{Q(x)} $ = $ \frac{5x^2}{x} $ = 5x, a polynomial.

So, $ \frac{P(x)}{Q(x)} $ is a polynomial sometimes.

We can, say Division is not always closed.

1/Q(x)

This could never be a polynomial. This is not even in the form of a polynomial. So, $ \frac{1}{Q(x)} $ is never a polynomial.

Hence, the answer.

7 0
2 years ago
A suit that sells for $300 in on sale of $240. Find the discount rate.
Gemiola [76]

Answer:

20% discount

Step-by-step explanation:

300 - 240 = 60

60 / 300 = 0.20

0.20 × 100 = 20

3 0
2 years ago
Will mark brainlyist
Setler [38]

Answer:

x=18.7

Step-by-step explanation:

x+17+5x+10+4x-34=180

10x-7=180

10x=187

x=18.7

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3 0
3 years ago
Read 2 more answers
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
Which point is a solution to y<4x+5
Alla [95]

Answer:

(1,-1)

Step-by-step explanation:

y < 4x+5

x = 1, y = -1 => -1 < -4+5 (T)

3 0
3 years ago
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